poj 1423
摘要:
stirling 公式。代码:#include<iostream>#include<fstream>#include<cmath>using namespace std;void read(){ int i,n,k; cin>>k; for(i=1;i<=k;i++) { cin>>n; cout<<(int)(log10(sqrt(2*3.1415926*n))+n*(log10(1.*n)-log10(exp(1.))))+1<<endl; }}int main(){ read(); return 0 阅读全文
posted @ 2011-03-28 16:17 宇宙吾心 阅读(264) 评论(0) 推荐(0)