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posted @ 2021-07-05 23:44
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posted @ 2021-07-05 20:50
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posted @ 2021-07-05 18:49
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posted @ 2021-07-05 18:39
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posted @ 2021-07-05 18:36
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posted @ 2021-07-05 18:25
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posted @ 2021-07-05 17:10
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posted @ 2021-07-05 17:00
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posted @ 2021-07-05 16:12
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posted @ 2021-07-05 16:08
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posted @ 2021-07-05 16:02
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posted @ 2021-07-05 15:46
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posted @ 2021-07-05 15:28
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posted @ 2021-07-05 15:24
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posted @ 2021-07-05 15:18
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posted @ 2021-07-05 15:08
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posted @ 2021-07-05 14:58
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一组数据,过滤出小于100的数,结果乘以2,并将结果汇总 <script> let buf = [10, 110, 20, 120, 30, 130]; let resBuf = buf.filter(n => n < 100).map(n => n * 2).reduce((value, n) = 阅读全文
posted @ 2021-07-05 14:36
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<script> let buf = [10, 110, 20, 120, 30, 130]; // value记录上次结果 let mapBuf = buf.reduce(function(value, n) { console.log(value, n); return 100 + n; }, 阅读全文
posted @ 2021-07-05 14:24
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<script> let buf = [10, 110, 20, 120, 30, 130]; let mapBuf = buf.map(function(n) { return n * 2; }) console.log(mapBuf); </script> 阅读全文
posted @ 2021-07-05 14:07
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