2024年2月3日
位运算找是否有相同元素
摘要： vector<string> words= {"abcw","asd","awgf","dggg"} for (int i = 0; i < n; ++i) { for (char ch : words[i]) { mask[i] |= 1 << (ch - 'a'); } } 给定string “ 阅读全文
posted @ 2024-02-03 17:06 zhangdudu 阅读(16) 评论(0) 推荐(0)