[python] 查找列表中重复的元素

a = [1, 2, 3, 2, 1, 5, 6, 5, 5, 5]
b = set(a)
for each_b in b:
    count = 0
    for each_a in a:
        if each_b == each_a:
            count += 1
    print(each_b, ": ", count)

===============================   

  结果:

  1 : 2
  2 : 2
  3 : 1
  5 : 4
  6 : 1

 

posted @ 2018-08-13 14:21  zhangdingqu  阅读(8517)  评论(0编辑  收藏  举报