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摘要: 【PAT B1001】害死人不偿命的3n+1猜想 #include<stdio.h> int main(){ int step = 0; int n; printf("输入n的值:\t"); scanf("%d", &n); while(n != 1){ if(n % 2 == 0){ n = n 阅读全文
posted @ 2020-01-13 16:33 ZHGQCN 阅读(217) 评论(0) 推荐(0)