2017年11月16日
Mysql下SELECT的结果集作为UPDATE的WHERE条件时的SQL语法
摘要： UPDATE `WarningSendMail` AS alias_1 INNER JOIN (SELECT * FROM `WarningSendMail` WHERE flag=1 AND topic_id LIKE "%2267%") AS alias_2 SET alias_1.topic_id = REPLACE(alias_1.topic_id,'|2267','') WHERE a... 阅读全文
posted @ 2017-11-16 19:20 陈泽泽 阅读(6147) 评论(0) 推荐(0)