第二次作业

6-7 删除字符串中数字字符

void delnum(char *s)
{
int i=0,j=0;
char *p=s;
for(i=0;*(s+i)!='\0';i++)
{
if(!((*(p+i)>='0')&&(*(p+i)<='9')))
{
*(s+j) = *(p+i);
j++;
}
}
s[j]='\0';
}

6-8 统计子串在母串出现的次数

int fun(char *str,char *substr)
{
int i,j,k,num;
for(i=0;str[i]!='\0';i++)
{
for(j=i,k=0;substr[k]==str[j];k++,j++)
{
if(substr[k+1]=='\0')
{
num++;
break;
}
}
}
return num;
}

6-9 字符串中除首尾字符外的其余字符按降序排列

int fun(char *s,int num)
{
int i,k,j,n=1;
char max=s[1];
for(i=1;i<num-1;i++)
{
for(j=1;j<num-1-i;j++)
{
if(s[j]<s[j+1])
{
k=s[j];s[j]=s[j+1];s[j+1]=k;
}
}
}
}

7-1 输出学生成绩

#include <stdio.h>
int main()
{
int i,n,a[n];
float sum = 0,average = 0,max,min;
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
sum = sum + a[i];
}
max = a[0];
min = a[0];
for(i=0;i<n;i++)
{
if(a[i]>max)
{
max=a[i];
}
if(a[i]<min)
{
min=a[i];
}
}

printf("average = %.2f\nmax = %.2f\nmin = %.2f",sum/n,max,min);
return 0;
}

7-1 计算职工工资

#include<stdio.h>
struct worker{
char name[15];
float bgong,fgong,x,w;
}s[10000];
int main()
{
int N,i;
scanf("%d",&N);
for(i=0;i<N;i++)
{
scanf("%s%f%f%f",&s[i].name,&s[i].bgong,&s[i].fgong,&s[i].x);
s[i].w=s[i].bgong+s[i].fgong-s[i].x;
printf("%s %.2f\n",s[i].name,s[i].w);
}
}

7-2 计算平均成绩

#include<stdio.h>
struct student{
char num[10],name[15];
int x;
}s[15];
int main()
{
int i,n,sum=0;
float average;
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%s%s%d",&s[i].num,&s[i].name,&s[i].x);
sum=sum+s[i].x;
}
average=sum*1.0/n;
printf("%.2f\n",average);
for(i=0;i<n;i++)
{
if(s[i].x<average)
printf("%s %s\n",s[i].name,s[i].num);
}
}

 

6-1 按等级统计学生成绩

int set_grade( struct student *p, int n ){
int count = 0, i;
for(i = 0;i<n;i++,p++){
if(p->score<60){
p->grade = 'D';
count++;
}
else if((p->score<70)&&(p->score>=60)){
p->grade = 'C';
}
else if((p->score<85)&&(p->score>=70)){
p->grade = 'B';
}
else{
p->grade = 'A';
}
}
return count;
}

6-2 结构体数组按总分排序

void calc(struct student *p,int n)
{
int i;
i=0;
for(i=0;i<n;i++)
{
p[i].sum = p[i].score[0]+ p[i].score[1]+ p[i].score[2];
}
}
void sort(struct student *p,int n)
{
int i,j;
i=0;
j=0;
struct student a ;

for(i=0;i<n-1;i++)
{
for(j=0;j<n-1-i;j++)
{
if(p[j].sum<p[j+1].sum)
{
a = p[j];
p[j] =p[j+1];
p[j+1] = a;
}
}
}
}

posted @ 2018-04-08 21:57  写作业  阅读(109)  评论(0编辑  收藏  举报