字典排序

dict1 = {
    'a':22,
    'f':2,
    'H':99,
    'zz':56
}

print(sorted(dict1.items(),key= lambda  k : k[1]))


print(sorted(zip(dict1.values(),dict1.keys())))

[('f', 2), ('a', 22), ('zz', 56), ('H', 99)]
[(2, 'f'), (22, 'a'), (56, 'zz'), (99, 'H')]

 

https://blog.csdn.net/weixin_44038167/article/details/103624245