A. Next Round

 

"Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).

Output

Output the number of participants who advance to the next round.

Examples
input
8 5
10 9 8 7 7 7 5 5
output
6
input
4 2
0 0 0 0
output
0
Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

 

1 #include <iostream>
2 int n,k,i,j,a[51];
3 using namespace std;
4 int main(){
5     cin>>n>>k;
6     while(n>i) cin>>a[i++];     //不一样的输入方式
7     while (a[j]&&a[j]>=a[k-1])  ++j;
8      cout<<j;
9 }

 

posted @ 2017-08-08 16:21  浅忆~  阅读(270)  评论(1编辑  收藏  举报