摘要: 迭代法-深度优先搜索(栈) class Solution: def binaryTreePaths(self, root: Optional[TreeNode]) -> List[str]: if not root: return [] # 如果根节点为空,直接返回空列表 stack = [(roo 阅读全文
posted @ 2024-03-23 18:41 Junior_bond 阅读(12) 评论(0) 推荐(0)
摘要: 自己写的,有字典很简单: class Solution: def isAnagram(self, s: str, t: str) -> bool: # 创建两个空字典来存储字符计数 s_dic = dict() t_dic = dict() # 遍历字符串s,计算每个字符出现的次数并存储在s_dic 阅读全文
posted @ 2024-03-23 17:52 Junior_bond 阅读(8) 评论(0) 推荐(0)