luogu 3690 【模板】 Link Cut Tree (动态树)

原来的代码有一些问题。

主要是对于不一定存在的边如何去判断,首先要保证在一个splay里,然后保证彼此之间直接联通且x的右儿子是空的

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #include<cstdlib>
 5 #include<cmath>
 6 #include<algorithm>
 7 #include<queue>
 8 #include<vector>
 9 #include<map>
10 #include<set>
11 #define ll long long
12 #define inf 2139062143
13 #define MAXN 300100
14 #define MOD 998244353
15 #define rep(i,s,t) for(register int i=(s),i##__end=(t);i<=i##__end;++i)
16 #define dwn(i,s,t) for(register int i=(s),i##__end=(t);i>=i##__end;--i)
17 #define ren for(register int i=fst[x];i;i=nxt[i])
18 #define pb(i,x) vec[i].push_back(x)
19 #define pls(a,b) (a+b)%MOD
20 #define mns(a,b) (a-b+MOD)%MOD
21 #define mul(a,b) (1LL*(a)*(b))%MOD
22 using namespace std;
23 inline int read()
24 {
25     int x=0,f=1;char ch=getchar();
26     while(!isdigit(ch)) {if(ch=='-') f=-1;ch=getchar();}
27     while(isdigit(ch)) {x=x*10+ch-'0';ch=getchar();}
28     return x*f;
29 }
30 int n,m;
31 int ch[MAXN][2],tag[MAXN],sum[MAXN],val[MAXN],fa[MAXN];
32 struct Lct
33 {
34     int which(int x) {return ch[fa[x]][1]==x;}
35     int isroot(int x) {return ch[fa[x]][0]!=x&&ch[fa[x]][1]!=x;}
36     void upd(int x) {sum[x]=val[x]^sum[ch[x][0]]^sum[ch[x][1]];}
37     void rev(int x) {tag[x]^=1;swap(ch[x][0],ch[x][1]);}
38     void pshd(int x)
39     {
40         if(!tag[x]) return ;tag[x]^=1;
41         if(ch[x][0]) rev(ch[x][0]);
42         if(ch[x][1]) rev(ch[x][1]);
43     }
44     void rotate(int x)
45     {
46         int f=fa[x],ff=fa[f],k=which(x);
47         if(!isroot(f)) ch[ff][ch[ff][1]==f]=x;fa[x]=ff;
48         ch[f][k]=ch[x][k^1],fa[ch[f][k]]=f,ch[x][k^1]=f,fa[f]=x;
49         upd(f);upd(x);
50     }
51     int st[MAXN],top;
52     void splay(int x)
53     {
54         st[top=1]=x;
55         for(int i=x;!isroot(i);i=fa[i]) st[++top]=fa[i];
56         dwn(i,top,1) pshd(st[i]);
57         for(int f;!isroot(x);rotate(x))
58             if(!isroot(f=fa[x])) rotate(which(x)==which(f)?f:x);
59     }
60     void access(int x) {for(int t=0;x;t=x,x=fa[x]){splay(x);ch[x][1]=t;upd(x);}}
61     void mkrt(int x) {access(x);splay(x);rev(x);}
62     void link(int x,int y) {mkrt(x);fa[x]=y;}
63     void split(int x,int y) {mkrt(x);access(y);splay(y);}
64     int find(int x)
65     {
66         access(x);splay(x);
67         while(ch[x][0]) pshd(x),x=ch[x][0];return x;
68     }
69     void cut(int x,int y) {split(x,y);if(fa[x]==y&&ch[y][0]==x&&!ch[x][1]) ch[y][0]=fa[x]=0,upd(y);}
70 }lct;
71 int main()
72 {
73     n=read(),m=read();int t,a,b;rep(i,1,n) val[i]=read();
74     while(m--)
75     {
76         t=read(),a=read(),b=read();
77         if(!t) {lct.split(a,b);printf("%d\n",sum[b]);}
78         if(t==1&&lct.find(a)!=lct.find(b)) lct.link(a,b);
79         if(t==2&&lct.find(a)==lct.find(b)) lct.cut(a,b);
80         if(t==3) val[a]=b,splay(a);
81     }
82 }
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posted @ 2018-02-08 21:38  jack_yyc  阅读(150)  评论(0编辑  收藏  举报