摘要:
select * from ( select * from (SELECT c.*,row_number() over(PARTITION BY c.reg_channels ORDER BY c.CREATE_TIME DESC) rn FROM app_user c ) where rn=1 )jj where jj.reg_channels='SAPP002' 阅读全文
posted @ 2016-07-06 10:11
也许还年轻
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