摘要: A. Primary Task 枚举所有情况即可 void solve(){ string s; cin >> s; if (s.substr(0, 2) != "10" || s.size() < 3 || s[2] == '0' || (s.size() < 4 && s[2] < '2')) 阅读全文
posted @ 2024-08-15 11:05 _Yxc 阅读(33) 评论(0) 推荐(0)