现有一个请求返回值的格式为:

{
	"success": true,
	"message": "",
	"code": 200,
	"result": {
		"returnCode": "03AD",
		"returnMsg": "AD3",
		"qrcode": "https://xxxxxxxxxx3xxxxxaaAAAAAA",
		"outTradeNo": "xxxxxx",
		"bankTradeNo": null,
		"msgId": "xxxx"
	},
	"timestamp": 16889873123011919
}

为了接收这个返回值,消费者这边建立了一个实体类接收这个返回值(考虑到返回值中的result内容会随着接口的改变而改变,使用了泛型):

@Data
public class Result<T> implements Serializable {

	private static final long serialVersionUID = 1L;

	private boolean success;

	private String message;

	private Integer code;
	
	private T result;

	private long timestamp;
}

使用RestTemplate.postForEntity()向生产者发送请求:

HttpHeaders headers = new HttpHeaders();
headers.put("TOKEN_SCRIPT",Arrays.asList(appToken));
OrderDTO orderDTO = txnReqBody.getOtherData();
HttpEntity<OrderDTO> httpEntity = new HttpEntity<>(orderDTO,headers);
ResponseEntity<Result> resultResponseEntity = restTemplateHttps.postForEntity(payQrCodeUrl, httpEntity, Result<PayOrderQueryResponse>.class); --会出现编译错误,不支持泛型

不使用泛型:
ResponseEntity<Result> resultResponseEntity = restTemplateHttps.postForEntity(payQrCodeUrl, httpEntity, Result.class);


发现result对象被解析成了LinkedHashMap

使用exchange加泛型解决问题

HttpHeaders headers = new HttpHeaders();
headers.put("TOKEN_SCRIPT",Arrays.asList(appToken));
OrderDTO orderDTO = txnReqBody.getOtherData();
HttpEntity<OrderDTO> httpEntity = new HttpEntity<>(orderDTO,headers);
ParameterizedTypeReference<Result<PayQrCodeResponse>> typeRef = new ParameterizedTypeReference<Result<PayQrCodeResponse>>() {};
ResponseEntity<Result<PayQrCodeResponse>> exchange = restTemplateHttps.exchange(payQrCodeUrl, HttpMethod.POST, httpEntity, typeRef);


解析正确。

posted on 2023-08-19 19:50  旅途的痕迹  阅读(578)  评论(0编辑  收藏  举报