191. 位1的个数 

 1 class Solution 
 2 {
 3 public:
 4     int hammingWeight(uint32_t n) 
 5     {
 6         int res = 0;
 7         for(int i = 0;i < 32;i ++) res += (n >> i) & 1;
 8         return res;
 9     }
10 };

 

posted @ 2020-04-03 23:06  Jinxiaobo0509  阅读(89)  评论(0)    收藏  举报