172. 阶乘后的零

 1 class Solution 
 2 {
 3 public:
 4     int trailingZeroes(int n) 
 5     {
 6         int res = 0;
 7         while(n >= 5)
 8         {
 9             res += n / 5;
10             n /= 5;
11         }
12         return res;
13     }
14 };

 

posted @ 2020-04-03 17:17  Jinxiaobo0509  阅读(112)  评论(0)    收藏  举报