摘要: double l = 0, r = inf, mid; while (r - l > 0.001) { mid = (l + r) / 2.0; int c = 0; for (int i = 0; i < n; i++) { c += int(arr[i] / mid); } if (c >= k 阅读全文
posted @ 2021-03-18 19:25 你看码!!! 阅读(2) 评论(0) 推荐(0)