08 2022 档案
摘要:修改列表的元素时,可以使用for 循环结合range n = int(input()) list_b = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] for i in range(len(list_b)): for y in range(len(list_b[i])): li
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摘要:num_list = []for i in range(1,16): if i == 13: continue else: num_list.append(str(i))str_num = ' '.join(num_list)
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摘要:list_a = [1, 2, 3] list_d = [i for i in list_a]#[1, 2, 3] list_e = [i*j for i in list_a for j in list_c]#[4,5,6,10,12,12,15,18] list_f = [i*j for i,j
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摘要:python中保留n位小数,可以使用round 函数 a = 34.564636856845754print(round(a, 2))print(round(a, 3))
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摘要:from django.test import TestCase# Create your tests here.class A: def __init__(self): self.a = "a" print("A")class B: def __init__(self): self.b = "b"
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