实验1 C语言输入输出和简单程序编写

实验1 C语言输入输出和简单程序编写

task1

程序task1_1.c

#include<stdio.h>
int main()
{
	printf(" O \n");
	printf("<H>\n");
	printf("I I\n");
	printf(" O \n");
	printf("<H>\n");
	printf("I I\n");

	return 0;
}

输出结果

程序task1_2.c

#include <stdio.h>
int main()
{
	printf(" O      O \n");
	printf("<H>    <H>\n");
	printf("I I    I I\n");
	return 0;
}

输出结果

task2

程序task2.c

#include <stdio.h>
int main()
{
	double a, b, c;
	scanf_s("%lf%lf%lf", &a, &b, &c);
	if (a+b>c && b+c>a && a+c>b)
		printf("能构成三角形\n");
	else
		printf("不能构成三角形\n");
	return 0;
}

输出结果

task3

程序task3.c

#include <stdio.h>
int main()
{
	char ans1, ans2; 
	printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) : ");
	ans1 = getchar(); 
	getchar(); 
	printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) : ");
	ans2 = getchar();
	if ((ans1 == 'y'||ans1 == 'Y') && (ans2 == 'y' || ans2 == 'Y')) 
		printf("\n罗马不是一天建成的, 继续保持哦:)\n");
	else
		printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
	return 0;
}

输出结果

task4

程序task4.c

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
int main()
{
	double x, y;
	char c1, c2, c3;
	int a1, a2, a3;
	scanf("%d %d %d", &a1, &a2, &a3);
	printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);
	scanf("%c %c %c", &c1, &c2, &c3);
	printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
	scanf("%lf %lf", &x, &y);
	printf("x = %lf, y = %lf\n", x, y);
	return 0;
}

输出结果

task5

程序task5.c

#include <stdio.h>
#include<math.h>
int main()
{
	int year;
	year = round(1000000000/60/60/24/365);
	printf("10亿秒约等于%d年\n", year);
	return 0;
}

输出结果

task6

实验程序task6.c

#include <stdio.h>
#include <math.h>
int main()
{
double x, ans;
while(scanf_s("%lf", &x) != EOF)
{
ans = pow(x, 365);
printf("%.2f的365次方: %.2f\n", x, ans);
printf("\n");
}
return 0;
}

输出结果

task7

实验程序task7.c

#include <stdio.h>
#include <math.h>
int main()
{
	double F, C;
	while (scanf_s("%lf", &C) != EOF)
	{
		F = C * 9 / 5 + 32;
		printf("摄氏度C = %.2f 时，华氏度F = %.2f\n", C, F);
		printf("\n");
	}
	return 0;
}

输出结果

task8

实验程序task8.c

#include <stdio.h>
#include <math.h>
int main()
{
	double ji, s, a, b, c, mian_ji;
	while (scanf_s("%lf %lf %lf", &a,&b,&c) != EOF)
	{
		s = (a + b + c) / 2;
		ji = s * (s - a) * (s - b) * (s - c);
		mian_ji = pow(ji, 0.5);
		printf("a = %.2f，b = %.2f, c = %.2f 时, mian_ji= %.2f\n", a, b, c, mian_ji);
		printf("\n");
	}
	return 0;
}

输出结果