摘要:
```python # 1. 使用while循环输出1 2 3 4 5 6 8 9 10 count = 0 while count < 10: count += 1 print(count) if count == 6: count+=1 continue #2. 求1-100的所有数的和 s = 0 count = 1 while count < 101: s += count count + 阅读全文
posted @ 2020-03-09 21:38
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2020年3月9日
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