摘要: 3-2 奇偶分家。输入一个正整数n,再输入n个非负整数,统计奇数和偶数各有多少个 #include<stdio.h> int main() { int count_odd, count_even, i, n, number; count_odd,count_even,i,n,number; coun 阅读全文
posted @ 2024-03-05 20:07 1ydd1 阅读(159) 评论(0) 推荐(0)