实验2
实验任务1
#include <stdio.h> #include <stdlib.h> #include <time.h>
#define N 5 #define N1 80 #define N2 35
int main() { int cnt; int random_major,random_no; srand(time(NULL)); // 以当前系统时间作为随机种子 cnt = 0; while(cnt < N) { random_major = rand() % 2; if(random_major) { random_no = rand() % N1 + 1; printf("20256343%04d\n", random_no);} else { random_no = rand() % N2 + 1; printf("20256136%04d\n", random_no); } cnt++; } return 0; }
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多次重复运行发现每次产生的随机数序列都不同
问题1:strand(time(NULL));的作用是设置随机数生成的种子
问题2:这个程序的功能是生成指定数量的随机学号
实验任务2
#include <stdio.h> int main() { int choice, quantity; float total_price = 0, amount_paid, change; while (1) { printf("\n自动饮料售卖机菜单:\n"); printf("1. 可乐 - 3 元/瓶\n"); printf("2. 雪碧 - 3 元/瓶\n"); printf("3. 橙汁 - 5 元/瓶\n"); printf("4. 矿泉水 - 2 元/瓶\n"); printf("0. 退出购买流程\n"); printf("请输入饮料编号: "); scanf("%d", &choice); if (choice == 0) break; if (choice < 1 || choice > 4) { printf("无效的饮料编号,请重新输入。\n"); continue; } printf("请输入购买的数量: "); scanf("%d", &quantity); if (quantity < 0) { printf("购买数量不能为负数,请重新输入。\n"); continue; } if(choice == 1 || choice == 2) total_price += 3 * quantity; else if(choice == 3) total_price += 5 * quantity; else total_price += 2 * quantity; printf("请投入金额: "); scanf("%f", &amount_paid); change = amount_paid - total_price; printf("本次购买总价: %.2f 元\n", total_price); printf("找零: %.2f 元\n", change); total_price = 0; } printf("感谢您的购买,欢迎下次光临!\n"); return 0; }
运行结果截图
问题1:如果去掉这行代码,后续购买的饮料总价会和之前的总价累加
问题2:第一处输入无效饮料编号时,跳过后续输入数量、计算价格等操作,直接回到循环开头,重新让用户输入饮料编号。第二处输入购买数量为负数时,跳过后续计算价格、投入金额等操作,直接回到循环开头,重新让用户输入饮料编号。
实验任务3
#include <stdio.h> int main() { char ch; while (scanf("%c", &ch) != EOF) { if (ch == 'r') { printf("stop!\n"); } else if (ch == 'g') { printf("go go go\n"); } else if (ch == 'y') { printf("wait a minute\n"); } else { printf("something must be wrong..\n"); } getchar(); } return 0; }
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实验任务4
#include <stdio.h> int main() { float expense, total = 0, max = 0, min = 20000.0; printf("输入今日开销,直到输入-1终止:\n"); while (1) { scanf("%f", &expense); if (expense == -1) break; total += expense; if (expense > max) max = expense; if (expense < min) min = expense; } printf("今日累计消费总额:%.1f\n", total); printf("今日最高一笔开销:%.1f\n", max); printf("今日最低一笔开销:%.1f\n", min); return 0; }
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实验任务5
#include <stdio.h> int main() { int a, b, c; while (scanf("%d %d %d", &a, &b, &c) != EOF) { if (a + b <= c || a + c <= b || b + c <= a) { printf("不能构成三角形\n"); } else { if (a == b && b == c) { printf("等边三角形\n"); } else if (a == b || a == c || b == c) { if ((a*a + b*b == c*c) || (a*a + c*c == b*b) || (b*b + c*c == a*a)) { printf("等腰直角三角形\n"); } else { printf("等腰三角形\n"); } } else if ((a*a + b*b == c*c) || (a*a + c*c == b*b) || (b*b + c*c == a*a)) { printf("直角三角形\n"); } else { printf("普通三角形\n"); } } } return 0; }
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实验任务6
#include <stdio.h> #include <stdlib.h> #include <time.h> int main() { int lucky_day, guess, count = 0; srand(time(NULL)); lucky_day = rand() % 30 + 1; printf("猜猜2025年11月哪一天是你的lucky day\n"); while (count < 3) { printf("开始喽,你有三次机会,猜吧(1~30): "); scanf("%d", &guess); count++; if (guess == lucky_day) { printf("哇,猜中了:)\n"); break; } else if (guess > lucky_day) { printf("你猜的日期晚了,你的lucky day在前面哦\n"); } else { printf("你猜的日期早了,你的lucky day还没到呢\n"); } if (count < 3) { printf("再猜(1~30): "); scanf("%d", &guess); count++; if (guess == lucky_day) { printf("哇,猜中了:)\n"); break; } else if (guess > lucky_day) { printf("你猜的日期晚了,你的lucky day在前面哦\n"); } else { printf("你猜的日期早了,你的lucky day还没到呢\n"); } } } if (count == 3 && guess != lucky_day) { printf("次数用光啦。偷偷告诉你,11月你的lucky day是%d号\n", lucky_day); } return 0; }
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