摘要:
declare @str varchar(14) set @str='20080210182031' select cast(left(@str,8) as datetime)+stuff(stuff(right(@str,6),3,0,':'),6,0,':') 输出结果 2008-02-10 18:20:31.000 阅读全文
posted @ 2009-02-19 17:31
大斌锅
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