摘要:
var uniq = function (arr) { var a = [], o = {}, i, v, len = arr.length; if (len < 2) { return arr; } for (i = 0; i < len; i++) { v = arr[i]; if (o[v] !== 1) { a.push(v); o[v] = 1; } } return a;}参见:http://... 阅读全文
posted @ 2012-03-22 13:49
仅此而已
阅读(278)
评论(0)
推荐(0)
浙公网安备 33010602011771号