螺旋矩阵
class Solution {
public List<Integer> spiralOrder(int[][] matrix) {
List<Integer> list = new ArrayList<>();
int m = matrix.length, n = matrix[0].length, i = 0, j = 0, cnt = 0;
list.add(matrix[0][0]);
matrix[0][0] = Integer.MIN_VALUE;
while(cnt < m*n-1){
while(j+1 < n && matrix[i][j+1] != Integer.MIN_VALUE){
j++;
cnt++;
list.add(matrix[i][j]);
matrix[i][j] = Integer.MIN_VALUE;
}
while(i+1 < m && matrix[i+1][j] != Integer.MIN_VALUE){
i++;
cnt++;
list.add(matrix[i][j]);
matrix[i][j] = Integer.MIN_VALUE;
}
while(j-1 >= 0 && matrix[i][j-1] != Integer.MIN_VALUE){
j--;
cnt++;
list.add(matrix[i][j]);
matrix[i][j] = Integer.MIN_VALUE;
}
while(i-1 >= 0 && matrix[i-1][j] != Integer.MIN_VALUE){
i--;
cnt++;
list.add(matrix[i][j]);
matrix[i][j] = Integer.MIN_VALUE;
}
}
return list;
}
}