摘要: CREATE TABLE "DB19C"."LAB_APPLY" ( "ID" VARCHAR2(100), "OUTPATIENT_NUM" VARCHAR2(100), "NAME" VARCHAR2(180), "ID_NUM" VARCHAR2(180), "CLINIC_EMERGENCY 阅读全文
posted @ 2022-01-13 16:53 小小菜包子 阅读(46) 评论(0) 推荐(0)