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poj3349 Snowflake Snow Snowflakes 哈希!哈希!看错题也能ac

Snowflake Snow Snowflakes
Time Limit: 4000MS   Memory Limit: 65536K
Total Submissions: 47379   Accepted: 12356

Description

You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your program will read information about a collection of snowflakes, and search for a pair that may be identical. Each snowflake has six arms. For each snowflake, your program will be provided with a measurement of the length of each of the six arms. Any pair of snowflakes which have the same lengths of corresponding arms should be flagged by your program as possibly identical.

Input

The first line of input will contain a single integer n, 0 < n ≤ 100000, the number of snowflakes to follow. This will be followed by n lines, each describing a snowflake. Each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow ake. The lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. For example, the same snowflake could be described as 1 2 3 4 5 6 or 4 3 2 1 6 5.

Output

If all of the snowflakes are distinct, your program should print the message:
No two snowflakes are alike.
If there is a pair of possibly identical snow akes, your program should print the message:
Twin snowflakes found.

Sample Input

2
1 2 3 4 5 6
4 3 2 1 6 5

Sample Output

Twin snowflakes found.

Source

 

这道题吧 哈哈哈 直接对雪花排序不旋转都能过 哈哈哈  尴尬了

以下代码是错的哈 但是ac了 没有旋转雪花 硬比的

    #include <iostream>  
    #include <cstdio>  
    #include <cstring>  
    #include <vector>  
    #include <algorithm>  
    #include <map>  
    #include <set>  
    using namespace std;  
    #define maxn 100010  
    #define pri 100007  
    vector<int> hash[pri];  
    int snow[maxn][6];  
    int n;  
    int cmp(int a,int b)  
    {  
        int k,j,ok1;  
        for(k=0; k<6; k++)  
        {  
            ok1=0;  
            for(j=0; j<6; j++)  
                if(snow[a][k]==snow[b][j])  
                {  
                    ok1=1;  
                    break;  
                }  
            if(ok1==0)  
                return 0;  
        }  
        return 1;  
    }  
    int main()  
    {  
        scanf("%d",&n);  
        int i,j;  
        for(i=0; i<n; i++)  
        {  
            for(j=0; j<6; j++)  
            scanf("%d",&snow[i][j]);  
        }  
        int sum,flag=1,key;  
        for(i=0; i<n&&flag!=0; i++)  
        {  
            sum=0;  
            for(j=0; j<6; j++)  
                sum+=snow[i][j];  
            key=sum%pri;  
            for(j=0; j<hash[key].size(); j++)  
            {  
                if(cmp(i,hash[key][j]))  
                {  
                    flag=0;  
                    puts("Twin snowflakes found.");  
                    break;  
                }  
            }  
            hash[key].push_back(i);  
        }  
        if(flag==1)  
            puts("No two snowflakes are alike.");  
        return 0;  
    }  

 

 

posted @ 2018-05-13 22:41  梦想飞的菜鸟  阅读(212)  评论(0)    收藏  举报