7.16

#include<iostream>
using namespace std;
int main() {
    int T[100];//用于确认所有身分是否都正确
    int N;//输入的身份证的个数
    cin >> N;
    int a = 0;
    char A[100][18];//储存输入的身份证号
    //首先将z值和校验码m的值对应起来
    int Z[17] = {7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2};
    char M[11] = { '1','0','X','9','8','7','6','5','4','3','2' };
    //进行统一的输入
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < 18; j++) {
            cin >> A[i][j];
        }
    }
    while (a < N) {
        char n;//最后的校验值
        int sum = 0;
        //检验是否都为数字
        int q = 1;//确认是否都为数字
        for (int i = 0; i < 17; i++) {
            if (A[a][i] - '0' < 0 || A[a][i] - '0' > 9) {
                q = 0;
            }
        }
        //不符合条件输出
        if (q == 0) {
            T[a] = 1;
            for (int i = 0; i < 18; i++) {
                cout << A[a][i];
            }
            cout << endl;
        }
        //加权求和
        else {
            for (int i = 0; i < 17; i++) {
                sum += (A[a][i] - '0') * Z[i];
            }
            n = M[sum % 11];
            if (n == A[a][17]) {
                T[a] = 0;
            }               
            else {
                T[a] = 1;
                for (int i = 0; i < 18; i++) {
                    cout << A[a][i];
                }
                cout << endl;
            }
        }
        a++;
        if (T == 0)
            cout << "All passed" << endl;
    }
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
 
int main()
{
string s;
double sum=100;
int count=0;
bool flag=false;
   cin>>s;
   int n=s.length();
   for(int i=0;i<n;i++)
   {
       char c=s.at(i);
       if(c=='-')
       {
           sum*=1.5;
           flag=true;
       }
       else{
           if(c=='2')
           {
               count++;
        }
        if(i==n-1&&(c-'0')%2==0)
        {
            sum*=2;
        }
       }
   }
   if(flag)
   {
         sum=sum*count/(n-1);
   }
   else{
       sum=sum*count/n;
   }
cout<<setiosflags(ios::fixed)<<setprecision(2)<<sum<<"%";//c++保留两位小数的方法
 
}