#include<bits/stdc++.h>
const int M=10007,N=50005;
typedef long long ll;
using namespace std;
int n,m,ans1,ans2,a[N],sum[N],f[2][N],q[N];
int jud(int x)
{
int tmp=0,sum=0;
for (int i=1;i<=n;i++)
{
sum+=a[i];
if (sum>x){tmp++;sum=a[i];}
if (tmp>m)return 0;
if (a[i]>x)return 0;
}
return 1;
}
void solve1()
{
int l=1,r=sum[n];
while (l<=r)
{
int mid=(l+r)>>1;
if (jud(mid)){ans1=mid;r=mid-1;}
else l=mid+1;
}
}
void solve2()
{
f[0][0]=1;
int pre,cur,tot;
for (int i=1;i<=m;i++)
{
pre=i&1;cur=pre^1;
int l=1,r=1;
q[1]=0;tot=f[cur][0];
for (int j=1;j<=n;j++)
{
while (l<=r&&sum[j]-sum[q[l]]>ans1)tot=(tot-f[cur][q[l++]]+M)%M;
f[pre][j]=tot;q[++r]=j;
tot=(tot+f[cur][j]+M)%M;
}
for (int j=n-1;j;j--)
{
if (sum[n]-sum[j]>ans1)break;
ans2=(ans2+f[pre][j]+M)%M;
}
memset(f[cur],0,sizeof(f[cur]));
}
printf("%d\n",ans2);
}
int main()
{
scanf("%d%d",&n,&m);
for (int i=1;i<=n;i++)scanf("%d",&a[i]);
for (int i=1;i<=n;i++)sum[i]=sum[i-1]+a[i];
solve1();
printf("%d ",ans1);
solve2();
}

posted on 2018-04-12 18:31  宣毅鸣  阅读(57)  评论(0编辑  收藏