摘要: str = '[111]dsfdsd[33333]'pattern = r"(\[.*?\])"; guid = re.findall(pattern,str ,re.M) if(len(guid)>0): guid = guid[0] guid = guid.replace('[','').replace(']','') 阅读全文
posted @ 2012-05-17 09:58 小さいです哥 阅读(8069) 评论(0) 推荐(1)