实验5

// 将图书信息写入文本文件data1.txt 

#include<stdio.h> #define N 5 #define M 80 typedef struct { char name[M]; char author[M]; }Book; int main() { Book x[N] = { {"一九八四", "乔治.奥威尔"}, {"美丽新世界", "赫胥黎"}, {"昨日的世界", "斯蒂芬.茨威格"}, {"万历十五年", "黄仁宇"}, {"一只特立独行的猪", "王小波"} }; int i; FILE *fp; // 以写的方式打开文本文件data1.txt fp = fopen("data1.txt", "w"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 将结构体数组x中的图书信息写到fp指向的文件data1.txt // 同时也输出到屏幕上 for(i=0; i<N; ++i) { fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author); printf("%-20s %-20s\n", x[i].name, x[i].author); } fclose(fp); return 0; }

 

 

 

task1_2

// 从文本文件data1.txt中读取图书信息,并打印输出到屏幕
#include<stdio.h>
#define N 5
#define M 80

typedef struct
{
    char name[M];
    char author[M];
}Book;

int main()
{
    Book x[N];
    int i;
    
    FILE *fp;
    
    // 以读的方式打开文本文件data1.txt
    fp = fopen("data1.txt", "r");
    
    // 如果打开文件失败,输出提示信息并返回
    if(fp == NULL)
    {
        printf("fail to open file\n");
        return 1;
    }
    
    // 从fp指向的文件data1.txt中读取信息到结构体数组x
    // 同时,把x的内容输出到屏幕上
    for(i=0; i<N; ++i)
    {
        fscanf(fp, "%s %s\n", x[i].name, x[i].author);
        printf("%-20s %-20s\n", x[i].name, x[i].author);
    }
    
    fclose(fp);
    
    return 0;
}

 

x[i].name不需要地址符,本身就是地址

 

task2_1

// 将图书信息以数据块方式写入二进制文件data2.dat
#include<stdio.h>
#define N 5
#define M 80

typedef struct
{
    char name[M];
    char author[M];
}Book;

int main()
{
    Book x[N] = { {"一九八四", "乔治.奥威尔"},
                  {"美丽新世界", "赫胥黎"},
                  {"昨日的世界", "斯蒂芬.茨威格"},
                  {"万历十五年", "黄仁宇"},
                  {"一只特立独行的猪", "王小波"}
                };
                
    int i;

    FILE *fp;

    // 以写的方式打开二进制文件data2.dat
    fp = fopen("data2.dat", "wb");

    // 如果打开文件失败,输出提示信息并返回
    if(fp == NULL)
    {
       printf("fail to open file\n");
       return 1;
    }

    // 将结构体数组x中的图书信息写以数据块方式写入文件
    // 把从地址x处开始sizeof(Book)×N个字节大小的数据块写入fp指向的文件
    fwrite(x, sizeof(Book), N, fp);

    fclose(fp);
    return 0;
}

 

1.生成了

2.可见

 

task2_2

// 从二进制文件data2.dat中读取图书信息,并打印输出到屏幕
#include<stdio.h>
#define N 5
#define M 80

typedef struct
{
    char name[M];
    char author[M];
}Book;

int main()
{
    Book x[N];
    int i;
    
    FILE *fp;
    
    // 以读的方式打开二进制文件data2.dat
    fp = fopen("data2.dat", "rb");
    
    // 如果打开文件失败,输出提示信息并返回
    if(fp == NULL)
    {
        printf("fail to open file\n");
        return 1;
    }
    
    // 从fp指向的文件中读取数据块到x对应的地址单元
    // 数据块大小为sizeof(Book)×N
    fread(x, sizeof(Book), N, fp);
    
    for(i=0; i<N; ++i)
    printf("%-20s%-20s\n", x[i].name, x[i].author);
    
    fclose(fp);
    
    return 0;
}

 

 

task3_1

#include<stdio.h>

int main()
{
    FILE *fin;
    char ch;
    int i=0;
    
    fin = fopen("data3_1.txt", "r");
    
    if(fin == NULL)
    {
        printf("fail to open data3_1.txt\n"); 
        return 1;
    }
    
     while( !feof(fin) )
    {
        ch = fgetc(fin);
        
        
        if(ch != ' ' && ch != '\n' && ch != '\t'&&
        ch!=EOF)
        {
            i++;
        }
        
    
        
    }
    printf("data3_1.txt中共包含字符数:%d",i);
    
    fclose(fin); 
    
    return 0;
}

 

task5

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

#define N 10

typedef struct
{
    long int id;
    char name[20];
    float objective;
    float subjective;
    float sum;
    char level[10];
}STU;

void input(STU s[], int n); 
void output(STU s[], int n); 
void process(STU s[], int n);

int main()
{
    STU stu[N];
    printf("从文件读入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分 (<=60)\n", N);
    input(stu, N);
    
    printf("\n对考生信息进行处理: 计算总分,确定等级\n");
    process(stu, N);
    
    printf("\n打印考生完整信息, 并保存到文件中");
    output(stu, N);
    
    return 0;
}

// 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分

void input(STU s[], int n)
{
    int i;
    FILE *fin;
    
    fin = fopen("examinee.txt", "r");
    if (fin == NULL)
    {
        printf("fail to open file\n");
        exit(0);
    }
    
    while (!feof(fin))
    {
        for (i = 0; i < n; i++)
        fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name, &s[i].objective, &s[i].subjective);
        
    }
    
    fclose(fin);
}

//输出考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级
// 不仅输出到屏幕上,还写到文本文件result.txt中
void output(STU s[], int n)
{
    FILE *fout;
    int i;
    
    // 输出到屏幕
    printf("\n");
    printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
    for (i = 0; i < n; i++)
    printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
    
    // 保存到文件
    fout = fopen("result.txt", "w");
    if (!fout)
    {
        printf("fail to open or create result.txt\n"); 
        exit(0);
    }
    
    fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
    
    for (i = 0; i < n; i++)
    fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
    
    fclose(fout);
}

// 对考生信息进行处理:计算总分,排序,确定等级
void process(STU s[], int n)
{
     int i,j;
     STU t;
     for(i=0;i<n;i++)
     {
         s[i].sum=(s[i].objective)+(s[i].subjective);
     }
     
     for(j=0;j<n-1;j++)
        for(i=0;i<n-j-1;i++)
            if(s[i].sum<s[i+1].sum)
            {
                t=s[i];
                s[i]=s[i+1];
                s[i+1]=t;
                
            }
    for(i=0;i<1;i++)
    {
       strcpy(    s[i].level,"优秀");
    }
    for(;i>=1&&i<5;i++)
        strcpy(s[i].level,"合格");
    for(;i<n;i++)
        strcpy(s[i].level,"不合格");
    
}

 

 

task6

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define N 5
#define M 80
typedef struct
{
    char id[20];
    char name[20];
    char banji[20];
}lucky;
int main()
{
    int i, j;
    lucky s[M];
    FILE* fin;
    FILE* fout;
    srand(time(0));
    fin = fopen("list.txt", "r");
    if (fin == NULL)
    {
        printf("fail to open file\n");
        return 1;
    }
    for (i = 0; i < M; i++)
    {
        fscanf(fin, "%s %s %s\n", s[i].id, s[i].name, s[i].banji);
    }

    fout = fopen("lucky.txt", "w");
    if (fout == NULL)
    {
        printf("fail to open file\n");
        return 1;
    }
    for (i = 0; i < N; i++)
    {
        j = rand() % 80;
        printf("%-20s %-20s %-20s\n", s[j].id, s[j].name, s[j].banji);
        fprintf(fout, "%-20s %-20s %-20s\n", s[j].id, s[j].name, s[i].banji);
    }
    fclose(fin);
    fclose(fout);
    return 0;

}

 

posted @ 2022-06-05 18:04  夏洁  阅读(9)  评论(1编辑  收藏  举报