摘要: jqueryAjax $.getJson(url,data,function(){}); $.get(url,data,function(){},'json'); $.ajax() $.ajax({ url:'userServlet', type:'get', data:'function=logi 阅读全文
posted @ 2020-10-29 21:24 pinkboy 阅读(72) 评论(0) 推荐(0)