leetcode 79: Populating Next Right Pointers in Each Node II

Populating Next Right Pointers in Each Node IIOct 28 '12

Follow up for problem "Populating Next Right Pointers in Each Node".

What if the given tree could be any binary tree? Would your previous solution still work?

Note:

  • You may only use constant extra space.

For example,
Given the following binary tree,

         1
       /  \
      2    3
     / \    \
    4   5    7

After calling your function, the tree should look like:

         1 -> NULL
       /  \
      2 -> 3 -> NULL
     / \    \
    4-> 5 -> 7 -> NULL

 

 

/**
 * Definition for binary tree with next pointer.
 * public class TreeLinkNode {
 *     int val;
 *     TreeLinkNode left, right, next;
 *     TreeLinkNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void connect(TreeLinkNode root) {
        // Start typing your Java solution below
        // DO NOT write main() function
        
        if(root==null) return;
        
        Queue<TreeLinkNode> q1 = new LinkedList<TreeLinkNode>();
        Queue<TreeLinkNode> q2 = new LinkedList<TreeLinkNode>();
        
        q1.offer( root );
        root.next = null;
        while( !q1.isEmpty() ) {
            TreeLinkNode t = q1.poll();
            if(t.left != null) q2.offer( t.left);
            if(t.right!=null) q2.offer( t.right );
            
            t.next = q1.isEmpty() ? null : q1.peek();
            
            if(q1.isEmpty()) {
                Queue<TreeLinkNode> temp = q1;
                q1 = q2;
                q2 = temp;
            }
        }
    }
}


 

posted @ 2013-02-17 17:16  西施豆腐渣  阅读(130)  评论(0编辑  收藏  举报