摘要:
select top 1800 * from AJ_AQJDSBwhere id >(select max(id) from (select top 2000 id from AJ_AQJDSB order by id) b)select top 1800 * from AJ_gcxx where id not in (select top 2000 id from AJ_gcxx orde... 阅读全文
posted @ 2010-03-18 16:55
新郎
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