mysql练习题
一、表关系
请创建如下表,并创建相关约束
二、操作表
1、自行创建测试数据

/* Navicat Premium Data Transfer Source Server : localhost Source Server Type : MySQL Source Server Version : 50624 Source Host : localhost Source Database : sqlexam Target Server Type : MySQL Target Server Version : 50624 File Encoding : utf-8 Date: 10/21/2016 06:46:46 AM */ SET NAMES utf8; SET FOREIGN_KEY_CHECKS = 0; -- ---------------------------- -- Table structure for `class` -- ---------------------------- DROP TABLE IF EXISTS `class`; CREATE TABLE `class` ( `cid` int(11) NOT NULL AUTO_INCREMENT, `caption` varchar(32) NOT NULL, PRIMARY KEY (`cid`) ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8; -- ---------------------------- -- Records of `class` -- ---------------------------- BEGIN; INSERT INTO `class` VALUES ('1', '三年二班'), ('2', '三年三班'), ('3', '一年二班'), ('4', '二年九班'); COMMIT; -- ---------------------------- -- Table structure for `course` -- ---------------------------- DROP TABLE IF EXISTS `course`; CREATE TABLE `course` ( `cid` int(11) NOT NULL AUTO_INCREMENT, `cname` varchar(32) NOT NULL, `teacher_id` int(11) NOT NULL, PRIMARY KEY (`cid`), KEY `fk_course_teacher` (`teacher_id`), CONSTRAINT `fk_course_teacher` FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`tid`) ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8; -- ---------------------------- -- Records of `course` -- ---------------------------- BEGIN; INSERT INTO `course` VALUES ('1', '生物', '1'), ('2', '物理', '2'), ('3', '体育', '3'), ('4', '美术', '2'); COMMIT; -- ---------------------------- -- Table structure for `score` -- ---------------------------- DROP TABLE IF EXISTS `score`; CREATE TABLE `score` ( `sid` int(11) NOT NULL AUTO_INCREMENT, `student_id` int(11) NOT NULL, `course_id` int(11) NOT NULL, `num` int(11) NOT NULL, PRIMARY KEY (`sid`), KEY `fk_score_student` (`student_id`), KEY `fk_score_course` (`course_id`), CONSTRAINT `fk_score_course` FOREIGN KEY (`course_id`) REFERENCES `course` (`cid`), CONSTRAINT `fk_score_student` FOREIGN KEY (`student_id`) REFERENCES `student` (`sid`) ) ENGINE=InnoDB AUTO_INCREMENT=53 DEFAULT CHARSET=utf8; -- ---------------------------- -- Records of `score` -- ---------------------------- BEGIN; INSERT INTO `score` VALUES ('1', '1', '1', '10'), ('2', '1', '2', '9'), ('5', '1', '4', '66'), ('6', '2', '1', '8'), ('8', '2', '3', '68'), ('9', '2', '4', '99'), ('10', '3', '1', '77'), ('11', '3', '2', '66'), ('12', '3', '3', '87'), ('13', '3', '4', '99'), ('14', '4', '1', '79'), ('15', '4', '2', '11'), ('16', '4', '3', '67'), ('17', '4', '4', '100'), ('18', '5', '1', '79'), ('19', '5', '2', '11'), ('20', '5', '3', '67'), ('21', '5', '4', '100'), ('22', '6', '1', '9'), ('23', '6', '2', '100'), ('24', '6', '3', '67'), ('25', '6', '4', '100'), ('26', '7', '1', '9'), ('27', '7', '2', '100'), ('28', '7', '3', '67'), ('29', '7', '4', '88'), ('30', '8', '1', '9'), ('31', '8', '2', '100'), ('32', '8', '3', '67'), ('33', '8', '4', '88'), ('34', '9', '1', '91'), ('35', '9', '2', '88'), ('36', '9', '3', '67'), ('37', '9', '4', '22'), ('38', '10', '1', '90'), ('39', '10', '2', '77'), ('40', '10', '3', '43'), ('41', '10', '4', '87'), ('42', '11', '1', '90'), ('43', '11', '2', '77'), ('44', '11', '3', '43'), ('45', '11', '4', '87'), ('46', '12', '1', '90'), ('47', '12', '2', '77'), ('48', '12', '3', '43'), ('49', '12', '4', '87'), ('52', '13', '3', '87'); COMMIT; -- ---------------------------- -- Table structure for `student` -- ---------------------------- DROP TABLE IF EXISTS `student`; CREATE TABLE `student` ( `sid` int(11) NOT NULL AUTO_INCREMENT, `gender` char(1) NOT NULL, `class_id` int(11) NOT NULL, `sname` varchar(32) NOT NULL, PRIMARY KEY (`sid`), KEY `fk_class` (`class_id`), CONSTRAINT `fk_class` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`) ) ENGINE=InnoDB AUTO_INCREMENT=17 DEFAULT CHARSET=utf8; -- ---------------------------- -- Records of `student` -- ---------------------------- BEGIN; INSERT INTO `student` VALUES ('1', '男', '1', '理解'), ('2', '女', '1', '钢蛋'), ('3', '男', '1', '张三'), ('4', '男', '1', '张一'), ('5', '女', '1', '张二'), ('6', '男', '1', '张四'), ('7', '女', '2', '铁锤'), ('8', '男', '2', '李三'), ('9', '男', '2', '李一'), ('10', '女', '2', '李二'), ('11', '男', '2', '李四'), ('12', '女', '3', '如花'), ('13', '男', '3', '刘三'), ('14', '男', '3', '刘一'), ('15', '女', '3', '刘二'), ('16', '男', '3', '刘四'); COMMIT; -- ---------------------------- -- Table structure for `teacher` -- ---------------------------- DROP TABLE IF EXISTS `teacher`; CREATE TABLE `teacher` ( `tid` int(11) NOT NULL AUTO_INCREMENT, `tname` varchar(32) NOT NULL, PRIMARY KEY (`tid`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8; -- ---------------------------- -- Records of `teacher` -- ---------------------------- BEGIN; INSERT INTO `teacher` VALUES ('1', '张磊老师'), ('2', '李平老师'), ('3', '刘海燕老师'), ('4', '朱云海老师'), ('5', '李杰老师'); COMMIT; SET FOREIGN_KEY_CHECKS = 1;
2、查询“生物”课程比“物理”课程成绩高的所有学生的学号;

SELECT T.student_id, student.sname FROM ( SELECT A.student_id FROM ( SELECT student_id, num FROM score LEFT JOIN course ON score.course_id = course.cid WHERE course.cname = '生物' ) AS A LEFT JOIN ( SELECT student_id, num FROM score LEFT JOIN course ON score.course_id = course.cid WHERE course.cname = '物理' ) AS B ON A.student_id = B.student_id WHERE A.num > if(ISNULL(B.num),0,B.num) ) AS T LEFT JOIN student ON T.student_id = student.sid
3、查询平均成绩大于60分的同学的学号、姓名和平均成绩;

-- 3、查询平均成绩大于60分的同学的学号和平均成绩; SELECT T.student_id, student.sname, T.平均成绩 FROM ( SELECT student_id, avg(num) AS 平均成绩 FROM score GROUP BY student_id HAVING 平均成绩 > 60 ) AS T LEFT JOIN student ON T.student_id = student.sid
4、查询所有同学的学号、姓名、选课数、总成绩;

SELECT student.sid, student.sname, count(1) as 选课数, IFNULL(sum(num),0) as 总成绩 FROM student LEFT JOIN score ON student.sid = score.student_id GROUP BY sid
5、查询姓“李”的老师的个数;

-- 5、查询姓“李”的老师的个数; SELECT COUNT(1) as c FROM teacher where tname LIKE '李%'
6、查询没学过“李平”老师课的同学的学号、姓名;

SELECT sid, sname FROM student WHERE sid NOT IN ( SELECT student_id FROM score WHERE course_id IN ( SELECT cid FROM teacher LEFT JOIN course ON teacher.tid = course.teacher_id WHERE teacher.tname = '李平老师' ) GROUP BY student_id )
7、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
思路:
先查到既选择001又选择002课程的所有同学
根据学生进行分组,如果学生数量等于2表示,两门均已选择

SELECT T.student_id, student.sname FROM ( SELECT student_id, count(1) AS c FROM score WHERE course_id = 1 OR course_id = 2 GROUP BY student_id HAVING c = 2 ) AS T LEFT JOIN student ON T.student_id = student.sid
8、查询学过“李平”老师所教的所有课的同学的学号、姓名;
同上,只不过将001和002变成
in
(叶平老师的所有课)

SELECT T.student_id, student.sname FROM ( SELECT student_id FROM score WHERE course_id IN ( SELECT cid FROM teacher LEFT JOIN course ON teacher.tid = course.teacher_id WHERE teacher.tname = "李平老师" ) GROUP BY student_id ) AS T LEFT JOIN student ON T.student_id = student.sid
9、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
同第1题

SELECT B.student_id, student.sname FROM ( SELECT T1.student_id FROM ( SELECT student_id, num AS a FROM score WHERE course_id = 1 ) AS T1 INNER JOIN ( SELECT student_id, num AS b FROM score WHERE course_id = 2 ) AS T2 ON T1.student_id = T2.student_id WHERE T1.a > T2.b ) AS B LEFT JOIN student ON B.student_id = student.sid
10、查询有课程成绩小于60分的同学的学号、姓名;

方法一:表联合 SELECT B.student_id, student.sname FROM ( SELECT student_id FROM score WHERE num < 60 GROUP BY student_id ) AS B LEFT JOIN student ON B.student_id = student.sid 方法二:子查询 SELECT sid, sname FROM student WHERE sid IN ( SELECT DISTINCT student_id FROM score WHERE num < 60 )
11、查询没有学全所有课的同学的学号、姓名;
思路:
在分数表中根据学生进行分组,获取每一个学生选课数量
如果数量 == 总课程数量,表示已经选择了所有课程

SELECT T.student_id, student.sname FROM ( SELECT student_id, COUNT(1) AS c FROM score GROUP BY student_id HAVING c = (SELECT count(1) FROM course) ) AS T LEFT JOIN student ON T.student_id = student.sid
12、查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名;
思路:
获取 001 同学选择的所有课程
获取课程在其中的所有人以及所有课程
根据学生筛选,获取所有学生信息
再与学生表连接,获取姓名

SELECT T.student_id, student.sname FROM ( SELECT student_id FROM score WHERE student_id != 1 AND course_id IN ( SELECT course_id FROM score WHERE student_id = 1 ) GROUP BY student_id ) AS T LEFT JOIN student ON T.student_id = student.sid
13、查询至少学过学号为“001”同学所有课的其他同学学号和姓名;
先找到和001的学过的所有人
然后个数 = 001所有学科 ==》 其他人可能选择的更多

SELECT score.student_id, student.sname, score.course_id, count(1) AS c FROM score LEFT JOIN student ON score.student_id = student.sid WHERE student_id != 1 AND course_id IN ( SELECT course_id FROM score WHERE student_id = 1 ) GROUP BY student_id HAVING c = ( SELECT COUNT(1) FROM score WHERE student_id = 1 ) 或者 SELECT T.student_id, student.sname FROM ( SELECT student_id, count(1) AS c FROM score WHERE student_id != 1 AND course_id IN ( SELECT course_id FROM score WHERE student_id = 1 ) GROUP BY student_id HAVING c = ( SELECT count(course_id) FROM score WHERE student_id = 1 ) ) AS T LEFT JOIN student ON T.student_id = student.sid
14、查询和“002”号的同学学习的课程完全相同的其他同学学号和姓名;
个数相同
002学过的也学过

SELECT T.student_id,student.sname FROM ( SELECT student_id from score where student_id = ( SELECT student_id from score GROUP BY student_id HAVING count(1)= (SELECT count(1) from score where student_id = 2) and student_id != 2 ) and course_id in (SELECT course_id from score where student_id = 2) GROUP BY student_id HAVING count(1) = (SELECT count(1) from score where student_id = 2) ) as T LEFT JOIN student ON T.student_id = student.sid
15、删除学习“叶平”老师课的score表记录;

DELETE FROM score WHERE course_id IN ( SELECT cid FROM teacher LEFT JOIN course ON teacher.tid = course.teacher_id WHERE tname = "李平老师" )
16、向SC表中插入一些记录,这些记录要求符合以下条件:①没有上过编号“002”课程的同学学号;②插入“002”号课程的平均成绩;
思路:
由于
insert
支持
inset
into
tb1(xx,xx)
select
x1,x2
from
tb2;
所有,获取所有没上过002课的所有人,获取002的平均成绩

INSERT INTO score (student_id, course_id, num) SELECT student_id, 2, ( SELECT avg(num) FROM score WHERE course_id = 2 ) FROM score WHERE course_id != 2 GROUP BY student_id
17、按平均成绩从低到高 显示所有学生的“生物”、“物理”、“体育”三门的课程成绩,按如下形式显示: 学生ID,生物,物理,体育,有效课程数,有效平均分;

SELECT sc.student_id , IFNULL( (SELECT num from score LEFT JOIN course ON score.course_id = course.cid where cname = '生物' and sc.student_id = student_id) ,0) as 生物 , IFNULL( (SELECT num FROM score LEFT JOIN course ON score.course_id = course.cid WHERE cname = '物理' and sc.student_id = student_id) ,0) as 物理, IFNULL( (SELECT num FROM score LEFT JOIN course ON score.course_id = course.cid where cname = '体育' and sc.student_id = student_id) ,0) as 体育, COUNT(sc.course_id), AVG(sc.num) as 平均分 FROM score as sc GROUP BY sc.student_id ORDER BY 平均分 ASC
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,课程名称,最高分,最低分;

SELECT
课程ID,
course.cname AS 课程名称,
最高分,
最低分
FROM
(
SELECT
course_id AS 课程ID,
max(num) AS 最高分,
min(num) AS 最低分
FROM
score
GROUP BY
course_id
) AS T
LEFT JOIN course ON T.课程ID = course.cid
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序;
思路:
case
when
..
then

SELECT cname as 课程名,平均分,及格率 from ( SELECT course_id,AVG(num) as 平均分,sum(CASE WHEN num>=60 then 1 ELSE 0 END)/count(course_id)*100 as 及格率 from score GROUP BY course_id ORDER BY 平均分 ASC,及格率 DESC ) as T LEFT JOIN course ON T.course_id = course.cid

SELECT teacher.tname, 平均分 FROM ( SELECT course_id, avg(IFNULL(num, 0)) AS 平均分 FROM score GROUP BY course_id ORDER BY 平均分 DESC ) AS T LEFT JOIN course ON T.course_id = course.cid LEFT JOIN teacher ON course.teacher_id = teacher.tid
21、查询各科成绩前三名的记录:(不考虑成绩并列情况)

SELECT course_id,num from score LEFT JOIN (SELECT sid, (select num from score as s2 where course_id = s1.course_id ORDER BY num desc LIMIT 0,1) as first, (SELECT num FROM score as s2 where course_id = s1.course_id ORDER BY num desc LIMIT 2,1) as end FROM score as s1 ) as T ON score.sid = T.sid where score.num >= T.end and score.num <= T.first order BY course_id asc,num desc
22、查询每门课程被选修的学生数;

SELECT course.cname AS 课程, 人数 FROM ( SELECT course_id, COUNT(1) AS 人数 FROM score GROUP BY course_id ) AS T LEFT JOIN course ON T.course_id = course.cid
23、查询出只选修了一门课程的全部学生的学号和姓名;

SELECT T.student_id, student.sname FROM ( SELECT student_id FROM score GROUP BY student_id HAVING COUNT(student_id) = 1 ) AS T LEFT JOIN student ON T.student_id = student.sid
24、查询男生、女生的人数;

SELECT ( SELECT COUNT(1) FROM student WHERE gender = '男' ) AS 男, ( SELECT COUNT(1) FROM student WHERE gender = '女' ) AS 女
25、查询姓“张”的学生名单;

SELECT * from student where sname like "张%"
26、查询同名同姓学生名单,并统计同名人数;

SELECT sname, count(1) AS 同名人数 FROM student GROUP BY sname HAVING count(1) > 1
27、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;

SELECT
course.cname AS 课程,
平均成绩
FROM
(
SELECT
course_id,
AVG(num) AS 平均成绩
FROM
score
GROUP BY
course_id
ORDER BY
平均成绩 ASC,
course_id DESC
) AS T
LEFT JOIN course ON T.course_id = course.cid
28、查询平均成绩大于85的所有学生的学号、姓名和平均成绩;

SELECT T.student_id AS 学号, student.sname AS 姓名, 平均成绩 FROM ( SELECT student_id, avg(num) AS 平均成绩 FROM score GROUP BY student_id HAVING AVG(IFNULL(num, 0)) > 85 ) AS T LEFT JOIN student ON T.student_id = student.sid
29、查询课程名称为“物理”,且分数低于60的学生姓名和分数;

SELECT student.sname AS 姓名, T.分数 FROM ( SELECT student_id, num AS 分数 FROM score LEFT JOIN course ON score.course_id = course.cid WHERE cname = "物理" AND num < 60 ) AS T LEFT JOIN student ON T.student_id = student.sid
30、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;

SELECT T.student_id AS 学号, student.sname AS 姓名, T.分数 FROM ( SELECT student_id, num AS 分数 FROM score WHERE course_id = 3 AND num > 80 ) AS T LEFT JOIN student ON T.student_id = student.sid
31、求选了课程的学生人数

SELECT count(DISTINCT student_id) from score
32、查询选修“张磊”老师所授课程的学生中,成绩最高的学生姓名及其成绩;

SELECT T.学号, student.sname AS 姓名, T.成绩 FROM ( SELECT student_id AS 学号, num AS 成绩 FROM score WHERE course_id IN ( SELECT cid FROM teacher LEFT JOIN course ON tid = course.teacher_id WHERE tname = '张磊老师' ) ORDER BY num DESC LIMIT 1 ) AS T LEFT JOIN student ON T.学号 = student.sid
33、查询各个课程及相应的选修人数;

SELECT course.cname AS 课程, T.选修人数 FROM ( SELECT course_id, COUNT(1) AS 选修人数 FROM score GROUP BY course_id ) AS T LEFT JOIN course ON T.course_id = course.cid
34、查询不同课程但成绩相同的学生的学号、课程号、学生成绩;

SELECT s1.student_id AS 学号, s1.course_id AS 课程1, s1.num AS 课程1得分, s2.course_id AS 课程2, s2.num AS 课程2得分 FROM score AS s1, score AS s2 WHERE s1.student_id = s2.student_id AND s1.course_id != s2.course_id AND s1.num = s2.num
35、查询每门课程成绩最好的前两名;

SELECT course_id,score.num from score LEFT JOIN ( select sid,num, (select num from score where course_id = s1.course_id ORDER BY num desc LIMIT 2,1) as s2end FROM score as s1 ) as T ON score.sid = T.sid where score.num >= T.s2end order BY score.course_id asc,score.num DESC
36、检索至少选修两门课程的学生学号;

SELECT student_id FROM score GROUP BY student_id HAVING count(1) > 1
37、查询全部学生都选修的课程的课程号和课程名;

SELECT course_id from score GROUP BY course_id HAVING count(1) = (SELECT COUNT(1) FROM student)
38、查询没学过“叶平”老师讲授的任一门课程的学生姓名;

SELECT T.student_id, student.sname FROM ( SELECT student_id FROM score WHERE course_id NOT IN ( SELECT cid FROM teacher LEFT JOIN course ON teacher.tid = course.teacher_id WHERE tname = '李平老师' ) GROUP BY student_id ) AS T LEFT JOIN student ON student.sid = T.student_id
39、查询两门或两门以上不及格课程的同学的学号及其平均成绩;

SELECT student_id, avg(num) AS 平均成绩 FROM score GROUP BY student_id HAVING sum( CASE WHEN num < 60 THEN 1 ELSE 0 END ) >= 2
40、检索“004”课程分数小于60,按分数降序排列的同学学号;

SELECT student_id, num FROM score WHERE course_id = 4 AND num < 60 ORDER BY num DESC
41、删除“002”同学的“001”课程的成绩;

delete from score where student_id = 2 and course_id = 1