实验1_C语言输入输出和简单程序应用编程2025

实验任务1

 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 int main()
 4 {
 5     printf(" o \n");
 6     printf("<H>\n");
 7     printf("I I\n");
 8     printf(" o \n");
 9     printf("<H>\n");
10     printf("I I\n");
11 
12     system("pause");
13 
14     return 0;
 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 int main()
 4 {
 5     printf(" o    o \n");
 6     printf("<H>  <H>\n");
 7     printf("I I  I I\n");
 8 
 9     system("pause");
10 
11     return 0;
12 }

2

3

实验任务2

 1 #include <stdio.h>
 2 int main()
 3 {
 4     double a, b, c;
 5     scanf("%lf%lf%lf", &a, &b, &c);
 6 
 7if(a+b>c&&a+c>b&&b+c>a)
 8          printf("能构成三角形\n");
 9     else
10          printf("不能构成三角形\n");
11     return 0;
12 }

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实验任务3

 

 1 #include <stdio.h>
 2 int main()
 3 {
 4     char ans1, ans2;
 5     
 6     printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有，输入n或N表示没有) : ");
 7     ans1 = getchar();
 8     
 9     getchar();
10     
11     printf("\n动手敲代码实践了没? (输入y或Y表示敲了，输入n或N表示木有敲) : ");
12     ans2 = getchar();
13     
14     if ((ans1==121||ans1==89)&&(ans2==121||ans2==89))
15        printf("\n罗马不是一天建成的, 继续保持哦:)\n");
16     else
17        printf("\n罗马不是一天毁灭的, 我们来建设吧\n");
18     return 0;
19 }

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 如果删去line9，在输入第一个字符后按回车会直接出现结果，因为回车赋值到了ans2

实验任务4

 1 #include<stdio.h>
 2 
 3 int main()
 4 {
 5     double x, y;
 6     char c1, c2, c3;
 7     int a1, a2, a3;
 8     
 9     scanf("%d%d%d", &a1, &a2, &a3);
10     printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3);
11     
12     scanf("%c%c%c", &c1, &c2, &c3);
13     printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
14     
15     scanf("%lf,%lf", &x, &y);
16     printf("x = %f, y = %lf\n",x, y);
17     
18     return 0;
19 }

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实验任务5

 

 1 #include<stdio.h>
 2 
 3 int main()
 4 {
 5     int year;
 6     year=1e10/(86400*365);
 7     if(year%10>=5)
 8         year=year/10+1;
 9     else
10         year=year/10;
11         
12     printf("10亿秒约等于%d年\n", year);
13     return 0;
14 }

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实验任务6

 

 1 #include <stdio.h>
 2 #include <math.h>
 3 
 4 int main()
 5 {
 6     double x, ans;
 7     
 8     while(scanf("%lf", &x) != EOF)
 9     {
10         ans = pow(x, 365);
11         printf("%.2f的365次方: %.2f\n", x, ans);
12         printf("\n");
13     }
14     
15     return 0;
16 }

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实验任务7

 

 1 #include <stdio.h>
 2 #include <math.h>
 3 
 4 int main()
 5 {
 6     double c, f;
 7     
 8     while(scanf("%lf", &c) != EOF)
 9     {
10         f = 9*c/5+32;
11         printf("摄氏度c = %.2f时，华氏度f = %.2f\n", c, f);
12         printf("\n");
13     }
14     
15     return 0;
16 }

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实验任务8

 1 #include <stdio.h>
 2 #include <math.h>
 3 
 4 int main()
 5 {
 6     double  a, b, c, s, area;
 7     
 8     while(scanf("%lf%lf%lf", &a,&b,&c) != EOF)
 9     {
10         s=(a+b+c)/2;
11         area = sqrt(s*(s-a)*(s-b)*(s-c));
12         printf("a = %.0f,b = %.0f,c = %.0f,area = %.3lf\n", a,b,c,area);
13         printf("\n");
14     }
15     
16     return 0;
17 }

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posted @ 2025-09-26 09:18  屑乃  阅读(60)  评论(1)    收藏  举报