摘要: A+B Coming Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5721 Accepted Submission(s): 3745 Pro 阅读全文
posted @ 2014-10-16 09:51 wojiaohuangyu 阅读(9) 评论(0) 推荐(0)
摘要: 测试你是否和LTC水平一样高 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13043 Accepted Submission(s): 432 阅读全文
posted @ 2014-10-15 22:41 wojiaohuangyu 阅读(5) 评论(0) 推荐(0)
摘要: hdu 1163 Eddy's digital Roots Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4634 Accepted Subm 阅读全文
posted @ 2014-10-12 19:54 wojiaohuangyu 阅读(16) 评论(0) 推荐(0)
摘要: Grandpa is Famous Time Limit: 2000MS Memory Limit: 30000KTotal Submissions: 7661 Accepted: 3857 Description The whole family was excited by the news. 阅读全文
posted @ 2014-09-14 21:40 wojiaohuangyu 阅读(11) 评论(0) 推荐(0)
摘要: zoj-1312 Prime Cuts #include<stdio.h> #include<string.h> #define max 1010 int main() { int n,m; int i,j,k,t; int a[1010]; int b[1010]; memset(a,0,size 阅读全文
posted @ 2014-09-14 21:38 wojiaohuangyu 阅读(8) 评论(0) 推荐(0)
摘要: 亲和串 #include<stdio.h> #include<string.h> int main() { char str1[101000]; char str2[101000]; char str3[202000]; while(gets(str1)!=NULL) { gets(str2); s 阅读全文
posted @ 2014-09-14 21:37 wojiaohuangyu 阅读(4) 评论(0) 推荐(0)
摘要: I Love This Game Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5596 Accepted Submission(s): 19 阅读全文
posted @ 2014-09-12 20:58 wojiaohuangyu 阅读(6) 评论(0) 推荐(0)
摘要: I Love This Game Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5596 Accepted Submission(s): 19 阅读全文
posted @ 2014-09-12 20:25 wojiaohuangyu 阅读(6) 评论(0) 推荐(0)
摘要: 我的生活我的梦,我的前途我的路,我的希望我的心,我的明天在何处? 理智的良言我为何听不见,上天的安排我为何摆不脱,命运的玩笑我为何开不起! 题记 为何,春叶飘落的时候,花儿没有忧伤?为何,微风吹拂的时候,听不见鸟儿的叫声?这春雨下得虽不是时候,但它毕竟是一如既往的润物细无声!昏暗的灯光哀伤着,等待着 阅读全文
posted @ 2014-08-25 17:32 wojiaohuangyu 阅读(11) 评论(0) 推荐(0)
摘要: http://acm.hdu.edu.cn/showproblem.php?pid=1719 本题为规律题,找到规律后一般比较好做 #include<stdio.h> int main() { int n; while(~scanf("%d",&n)){ if(n==1||n==2){ printf 阅读全文
posted @ 2014-08-25 16:44 wojiaohuangyu 阅读(4) 评论(0) 推荐(0)