Number Steps 代码语言：c

Number Steps

时限：1000ms 内存限制：10000K  总时限：3000ms

描述：

Starting from point (0,0) on a plane, we have written all non-negative integers 0, 1, 2,... as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued.

You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0...5000.

输入：

there is x, and y representing the coordinates (x, y) of a point.

输出：

write the number written at that point or write No Number if there is none.

输入样例：

4 2
6 6
3 4

输出样例：

6
12
No Number

提示：

 

来源：

代码：

1. #include <stdio.h>
2. #include <stdlib.h>
3. int main()
4. {
5. int x,y;
6. scanf("%d%d",&x,&y);
7. if(x%2==0&&y%2==0&&x>=y)
8. printf("%d\n",x+y);
9. else if(x%2!=0&&y%2!=0&&x>=y)
10. printf("%d\n",x+y-1);
11. else printf("No Number\n");
12. return 0;
13. }