摘要: 如下 select x.*,count(1) from ( -- select substr(t.attachmentpath,-3,)v from COMM_ATTACHMENT t select substr(t.attachmentpath,instr(t.attachmentpath,'.' 阅读全文
posted @ 2023-04-19 18:26 xh_Blog 阅读(31) 评论(0) 推荐(0)