实验4

1.a是连续存放的,每个元素占用4个字节。

2.b是连续存放的,每个元素占用一个字节。

3.是一样的。

#include<stdio.h>
#define N 4
int main() {
	int a[N] = { 2, 0, 2, 2 };
	char b[N] = { '2', '0', '2', '2' }; 
	int i; printf("sizeof(int) = %d\n", sizeof(int));
	printf("sizeof(char) = %d\n", sizeof(char)); 
	printf("\n"); // 输出数组a中每个元素的地址、值 
	for (i = 0; i < N; ++i) 
		printf("%p: %d\n", &a[i], a[i]);
	printf("\n"); // 输出数组b中每个元素的地址、值 
	for (i = 0; i < N; ++i)
		printf("%p: %c\n", &b[i], b[i]); printf("\n"); // 输出数组名a和b对应的值 
	printf("a = %p\n", a);
	printf("b = %p\n", b);
	return 0; }

  

1.是按行连续存放的,每个元素占4个字节

2.是按行连续存放的,每个元素占用一个字节

#include<stdio.h>
#define N 2
#define M 3
int main() {
int a[N][M] = { {1, 2, 3}, {4, 5, 6} };
char b[N][M] = { {'1', '2', '3'}, {'4', '5', '6'} };
int i, j; // 输出二维数组a中每个元素的地址和值
for (i = 0; i < N; ++i)
	for (j = 0; j < M; ++j) 
		printf("%p: %d\n", &a[i][j], a[i][j]);
printf("\n"); // 输出二维数组a中每个元素的地址和值
for (i = 0; i < N; ++i) 
	for (j = 0; j < M; ++j)
		printf("%p: %c\n", &b[i][j], b[i][j]); 
return 0;
}

  

 

#include<stdio.h>

int days_of_year(int year,int month,int day);

int main()
{
	int year,month,day;int days;
	
	while(scanf_s("%d%d%d",&year,&month,&day)!=EOF)
	{
		days=days_of_year(year,month,day);
		printf("%4d-%02d-%02d是这一年的第%d天.\n\n",year,month,day,days);
	}
	
	return 0;
}

int days_of_year(int year,int month,int day)
{
    int i,days=0;
    int mon[12]={0,31,28,31,30,31,30,31,31,30,31,30};
	for(i=1;i<month;i++)
	{
	    if((year%4==0)&&(year%100!=0)||year%400==0)
	    {
	    	mon[2]++;
		}
		days+=mon[i];
    }
    days+=day;
    return days;
}

  

#include<stdio.h>
#define N 5

void input(int x[],int n);
void output(int x[],int n);
double average(int x[],int n);
void sort(int x[],int n);

int main()
{
	int scores[N];
	double ave;
	
	printf("录入%d个分数:\n",N);
	input(scores,N);
	
	printf("\n输出课程分数:\n");
	output(scores,N);
	
	printf("\n课程分数处理:计算均分、排序...\n");
	ave=average(scores,N);
	sort(scores,N);
	
	printf("\n输出课程均分:%.2f\n",ave);
	printf("\n输出课程分数(高—>低):\n");
	output(scores,N);
	
	return 0;
}

void input(int x[],int n)
{
	int i;
	for(i=0;i<n;++i)
	    scanf_s("%d",&x[i]);
}

void output(int x[],int n)
{
	int i;
	for(i=0;i<n;++i)
	    printf("%d ",x[i]);
	    
	printf("\n");
}

double average(int x[],int n)
{
	int sum=0,i;double s;
	for(i=0;i<n;++i)
	{
		sum+=x[i];
	}
	s=1.0*sum/n;
	return s;
}

void sort(int x[],int n)
{
	int i,j,k;
	for(i=0;i<n;++i)
	{
        for(j=0;j<i;j++)
        {
        			if(x[i]>x[j])
		{
			k=x[i];
			x[i]=x[j];
			x[j]=k;
		}
		}
	}
}

  

#include<stdio.h>

void dec2n(int x, int n);

int main()
{
	int x;

	printf("输入一个十进制整数:");
	scanf_s("%d", &x);

	dec2n(x, 2);
	printf("\n");
	dec2n(x, 8);
	printf("\n");
	dec2n(x, 16);
	printf("\n");

	return 0;
}

void dec2n(int x, int n)
{
	int a, b; char m[16] = { "0123456789ABCDEF" };
	a = x / n;
	b = x % n;
	if (a == 0)
	{
		printf("%c", m[b]);
	}
	else
	{
		dec2n(a, n);
		printf("%c", m[b]);
	}
}

  

#include<stdio.h>

void ulmatrix(int n);

int main()
{
int n; int a[10][10];
printf("Enter n: ");
while (scanf_s("%d", &n) != EOF)
{
ulmatrix(n);
printf("\nEnter n: ");
}

return 0;
}

void ulmatrix(int n)
{
int i, j, a[10][10];
for (i = 0; i < n; i++)
{
for (j = 0; j < n; j++)
{
if (i <= j)
{
a[i][j] = i + 1;
}
else
{
a[i][j] = j + 1;
}
printf("%d ", a[i][j]);
}
printf("\n");
}
}

#include<stdio.h>
#define N 80

int main()
{
	char views1[N]="hey,c,i hate u.";
	char views2[N]="hey,c,i love u.";
	char view[N];int i=0;
	
	printf("original views:\n");
	printf("views1: %s\n",views1);
	printf("views2: %s\n",views2);
    
    for(i=0;i<N;i++)
    {
    	view[i]=views1[i];
    	views1[i]=views2[i];
    	views2[i]=view[i];
	}
	
	printf("\nswapping...\n\n");
	printf("views1: %s\n",views1);
	printf("views2: %s\n",views2);
    
    return 0;
} 

  

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>

#define N 5
#define M 20

void bubble_sort(char str[][M], int n);

int main()
{
	char name[][M] = { "Bob","Bill","Joseph","Taylor","George" };
	int i;

	printf("输入初始名单:\n");
	for (i = 0; i < N; i++)
		printf("%s\n", name[i]);

	printf("\n排列中...\n");
	bubble_sort(name, N);

	printf("\n按字典序输出名单:\n");
	for (i = 0; i < N; i++)
		printf("%s\n", name[i]);

	return 0;
}

void bubble_sort(char str[][M], int n)
{
	int i, j; char mid[M];
	for (i = 0; i < N; i++)
	{
		for (j = 0; j < i; j++)
		{
			if (strcmp(str[j], str[j + 1]) > 0)
			{
				strcpy(mid, str[j]);
				strcpy(str[j], str[j + 1]);
				strcpy(str[j + 1], mid);
			}
		}
	}
}

  

 

posted @ 2022-05-08 16:11  xcy1234  阅读(7)  评论(1编辑  收藏  举报