摘要：
26进制class Solution {public: int titleToNumber(string s) { int n = 0; for (int i = 0; i < s.size(); i++) { n = n * 26 + s[i... 阅读全文
posted @ 2014-12-28 20:47 1957 阅读(182) 评论(0) 推荐(0)
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摘要：
26进制class Solution {public: int titleToNumber(string s) { int n = 0; for (int i = 0; i < s.size(); i++) { n = n * 26 + s[i... 阅读全文
posted @ 2014-12-28 20:47 1957 阅读(182) 评论(0) 推荐(0) |
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