【模板】多标记线段树

维护一个长度为 N 的序列，支持区间加和、区间乘积、查询区间和操作。

代码如下

#include <bits/stdc++.h>
using namespace std;
const int maxn=1e5+10;

inline int read(){
	int x=0,f=1;char ch;
	do{ch=getchar();if(ch=='-')f=-1;}while(!isdigit(ch));
	do{x=x*10+ch-'0';ch=getchar();}while(isdigit(ch));
	return f*x;
}

int n,m,a[maxn];long long mod;
struct node{
	#define ls(x) t[x].lc
	#define rs(x) t[x].rc
	int lc,rc;
	long long sum,stag,mtag;
}t[maxn<<1];
int tot,root;
inline void pushup(int o){t[o].sum=(t[ls(o)].sum+t[rs(o)].sum)%mod;}
inline void pushdown(int o,int l,int r){
	int mid=l+r>>1;
	t[ls(o)].sum=(t[ls(o)].sum*t[o].mtag%mod+(mid-l+1)*t[o].stag%mod)%mod;
	t[ls(o)].mtag=t[ls(o)].mtag*t[o].mtag%mod;
	t[ls(o)].stag=(t[ls(o)].stag*t[o].mtag%mod+t[o].stag)%mod;
	t[rs(o)].sum=(t[rs(o)].sum*t[o].mtag%mod+(r-mid)*t[o].stag%mod)%mod;
	t[rs(o)].mtag=t[rs(o)].mtag*t[o].mtag%mod;
	t[rs(o)].stag=(t[rs(o)].stag*t[o].mtag%mod+t[o].stag)%mod;
	t[o].stag=0,t[o].mtag=1;
}
int build(int l,int r){
	int o=++tot;
	t[o].mtag=1;
	if(l==r){t[o].sum=a[l];return o;}
	int mid=l+r>>1;
	ls(o)=build(l,mid),rs(o)=build(mid+1,r);
	pushup(o);
	return o;
}
void modify(int o,int l,int r,int x,int y,long long val,int mode){//1->add 2->mul
	if(l==x&&r==y){
		if(mode==1)t[o].sum=(t[o].sum+(r-l+1)*val)%mod,t[o].stag=(t[o].stag+val)%mod;
		else t[o].sum=t[o].sum*val%mod,t[o].mtag=t[o].mtag*val%mod,t[o].stag=t[o].stag*val%mod;
		return;
	}
	int mid=l+r>>1;
	pushdown(o,l,r);
	if(y<=mid)modify(ls(o),l,mid,x,y,val,mode);
	else if(x>mid)modify(rs(o),mid+1,r,x,y,val,mode);
	else modify(ls(o),l,mid,x,mid,val,mode),modify(rs(o),mid+1,r,mid+1,y,val,mode);
	pushup(o);
}
long long query(int o,int l,int r,int x,int y){
	if(l==x&&r==y)return t[o].sum;
	int mid=l+r>>1;
	pushdown(o,l,r);
	if(y<=mid)return query(ls(o),l,mid,x,y);
	else if(x>mid)return query(rs(o),mid+1,r,x,y);
	else return query(ls(o),l,mid,x,mid)+query(rs(o),mid+1,r,mid+1,y);
}

int main(){
	n=read(),mod=read();
	for(int i=1;i<=n;i++)a[i]=read();
	root=build(1,n);
	m=read();
	while(m--){
		int opt=read();
		if(opt==1){
			int l=read(),r=read(),val=read();
			modify(root,1,n,l,r,val,2);
		}else if(opt==2){
			int l=read(),r=read(),val=read();
			modify(root,1,n,l,r,val,1);
		}else{
			int l=read(),r=read();
			printf("%lld\n",query(root,1,n,l,r)%mod);
		}
	}
	return 0;
}