实验1

实验1现代C++编程初体验

实验任务一 :

task1.cpp:

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>

template <typename T>
void output(const T &c);
void test1();
void test2();
void test3();

int main()
{
    std::cout << "测试1: \n";
    test1();
    std::cout << "\n测试2: \n";
    test2();
    std::cout << "\n测试3: \n";
    test3();
}

template <typename T>
void output(const T &c)
{
    for (auto &i : c)
    {
        std::cout << i << ' ';
    }
    std::cout << '\n';
}

void test1()
{
    using namespace std;

    string s0{"0123456789"};
    cout << "s0 = " << s0 << endl;

    string s1(s0);

    reverse(s1.begin(), s1.end());
    cout << "s1 = " << s1 << endl;

    string s2(s0.size(), ' ');
    reverse_copy(s0.begin(), s0.end(), s2.begin());
    cout << "s2 = " << s2 << endl;
}

void test2()
{
    using namespace std;

    vector<int> v0{2, 0, 4, 9};
    cout << "v0: ";
    output(v0);

    vector<int> v1{v0};
    reverse(v1.begin(), v1.end());
    cout << "v1: ";
    output(v1);

    vector<int> v2{v0};
    reverse_copy(v0.begin(), v0.end(), v2.begin());
    cout << "v2: ";
    output(v2);
}

void test3()
{
    using namespace std;

    vector<int> v0{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
    cout << "v0: ";
    output(v0);

    vector<int> v1{v0};
    rotate(v1.begin(), v1.begin() + 1, v1.end());
    cout << "v1: ";
    output(v1);

    vector<int> v2{v0};
    rotate(v2.begin(), v2.begin() + 2, v2.end());
    cout << "v2: ";
    output(v2);

    vector<int> v3{v0};
    rotate(v3.begin(), v3.end() - 1, v3.end());
    cout << "v3: ";
    output(v3);

    vector<int> v4{v0};
    rotate(v4.begin(), v4.end() - 2, v4.end());
    cout << "v4: ";
    output(v4);
}

运行截图:

任务1

问题 :

  1. reverse 和 reverse_copy 有什么区别?

​ 答: reverse是把该区间内容反转,reverse_copy是不修改原区间,获取其反转后结果的复制

  1. rotate 算法是如何改变元素顺序的?它的三个参数分别代表什么?

​ 答: 以中间参数为旋转点,交换左右区间。三个参数代表左边界,旋转点,右边界

实验任务2

task2.cpp:

#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
#include <iomanip>
#include <cstdlib>
#include <ctime>

template <typename T>
void output(const T &c);
int generate_random_number();
void test1();
void test2();

int main()
{
    std::srand(std::time(0));
    std::cout << "测试1: \n";
    test1();
    std::cout << "\n测试2: \n";
    test2();
}

template <typename T>
void output(const T &c)
{
    for (auto &i : c)
    {
        std::cout << i << ' ';
    }
    std::cout << '\n';
}

int generate_random_number()
{
    return std::rand() % 101;
}

void test1()
{
    using namespace std;

    vector<int> v0(10);
    generate(v0.begin(), v0.end(), generate_random_number);
    cout << "v0: ";
    output(v0);

    vector<int> v1{v0};
    sort(v1.begin(), v1.end());
    cout << "v1: ";
    output(v1);

    vector<int> v2{v0};
    sort(v2.begin() + 1, v2.end() - 1);
    cout << "v2: ";
    output(v2);
}

void test2()
{
    using namespace std;

    vector<int> v0(10);
    generate(v0.begin(), v0.end(), generate_random_number);
    cout << "v0: ";
    output(v0);

    auto min_iter = min_element(v0.begin(), v0.end());
    auto max_iter = max_element(v0.begin(), v0.end());
    cout << "最小值: " << *min_iter << endl;
    cout << "最大值: " << *max_iter << endl;

    auto ans = minmax_element(v0.begin(), v0.end());
    cout << "最小值: " << *(ans.first) << endl;
    cout << "最大值: " << *(ans.second) << endl;

    double avg1 = accumulate(v0.begin(), v0.end(), 0.0) / v0.size();
    cout << "均值: " << fixed << setprecision(2) << avg1 << endl;

    sort(v0.begin(), v0.end());
    
    double avg2 = accumulate(v0.begin() + 1, v0.end() - 1, 0.0) / (v0.size() - 2);
    cout << "去掉最大值、最小值之后,均值: " << avg2 << endl;
}

运行截图:

任务2

问题:

  1. generate 算法的作用是什么?

​ 答: 使用第三个参数生成元素来更新前两个参数划分的区间里的元素

  1. minmax_element 和分别调用min_element 、 max_element 相比,有什么优势?

​ 答: minmax_element只需要一次遍历,性能优

​ min_element 和 max_element 需要额外遍历一次,分两次调用性能差。

  1. generate 第3个参数 用法,与使用自定义函数 generate_random_number 相比,lambda表达式适用场景是什么?

    答: 不想为了一个只使用一次的函数命名,需要捕获外部变量

实验任务3:

task3.cpp:

#include <iostream>
#include <string>
#include <algorithm>
#include <cctype>

unsigned char func(unsigned char c);
void test1();
void test2();

int main()
{
    std::cout << "测试1: 字符串大小写转换\n";
    test1();
    std::cout << "\n测试2: 字符变换\n";
    test2();
}

unsigned char func(unsigned char c)
{
    if (c == 'z')
        return 'a';
    if (c == 'Z')
        return 'A';
    if (std::isalpha(c))
        return static_cast<unsigned char>(c + 1);
    return c;
}
void test1()
{
    std::string s1{"Hello World 2049!"};
    std::cout << "s1 = " << s1 << '\n';

    std::string s2;
    for (auto c : s1)
        s2 += std::tolower(c);
    std::cout << "s2 = " << s2 << '\n';

    std::string s3;
    for (auto c : s1)
        s3 += std::toupper(c);
    std::cout << "s3 = " << s3 << '\n';
}
void test2()
{
    std::string s1{"I love cosmos!"};
    std::cout << "s1 = " << s1 << '\n';
    
    std::string s2(s1.size(), ' ');
    std::transform(s1.begin(), s1.end(), s2.begin(), func);
    std::cout << "s2 = " << s2 << '\n';
}

运行截图:

任务3

问题:

  1. 自定义函数func功能是什么?

    答: 将26字母作为环,返回输入字符在环上的下一个字符

  2. tolower和toupper功能分别是什么?

    答: tolower的功能是:将输入字符转换为小写字母。

    toupper的功能是:将输入字符转换为大写字母。

  3. transform的4个参数分别是什么?如果把第三个参数s2.begin()改成s1.begin(),有何区别

    答: transform 的4个参数意义分别是:

    ​ 第一个参数:输入区间起始迭代器(如 s1.begin())。

    ​ 第二个参数:输入区间结束迭代器(如 s1.end())。

    ​ 第三个参数:输出区间起始迭代器(如 s2.begin())。

    ​ 第四个参数:用于变换的函数(如 func)。

    如果把第3个参数 s2.begin() 改成 s1.begin(),区别是:

    ​ 原来是将变换结果写入 s2(不会影响 s1)。

    ​ 改成 s1.begin() 后,变换结果会直接替换 s1 原有内容。

实验任务4:

task4.cpp:

#include <iostream>
#include <string>
#include <algorithm>

bool is_palindrome(const std::string &s);
bool is_palindrome_ignore_case(const std::string &s);

int main()
{
    using namespace std;
    string s;

    while (cin >> s)
    {
        cout << boolalpha
             << "区分大小写: " << is_palindrome(s) << "\n"
             << "不区分大小写: " << is_palindrome_ignore_case(s) << "\n\n";
    }
}

bool is_palindrome(const std::string &s) {
    size_t midle_len = s.size() / 2;
    for(size_t i = 0; i < midle_len; i++) {
        if(s[i] != s[s.size() - i - 1]) return false;
    }
    return true;
}
bool is_palindrome_ignore_case(const std::string &s) {
    size_t midle_len = s.size() / 2;
    for(size_t i = 0; i < midle_len; i++) {
        if (std::tolower(s[i]) != std::tolower(s[s.size() - i - 1]))
        {
            return false;
        }
    }
    return true;
}

运行截图:

任务4

问题:

  1. 使用 cin >> s输入时,输入的字符串中不能包含空格。如果希望测试字符串包含空格(如 oop ),代码应如何调整?

    答 :

    将输入方式改为:

    std::getline(std::cin, s);
    

实验任务5:

task5.cpp:

#include <iostream>
#include <string>
#include <algorithm>

const char array[37] = {"0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"};

std::string dec2n(int x, int n = 2);
int main()
{
    int x;
    while (std::cin >> x)
    {
        std::cout << "十进制: " << x << '\n'
                  << "二进制: " << dec2n(x) << '\n'
                  << "八进制: " << dec2n(x, 8) << '\n'
                  << "十二进制: " << dec2n(x, 12) << '\n'
                  << "十六进制: " << dec2n(x, 16) << '\n'
                  << "三十二进制: " << dec2n(x, 32) << "\n\n";
    }
}

std::string dec2n(int x, int n)
{
    if (x == 0)
        return "0";
    std::string res;
    while (x > 0)
    {
        int r = x % n;
        res += array[r];
        x /= n;
    }
    std::reverse(res.begin(), res.end());
    return res;
}

运行截图:

任务5

实验任务6:

task6.cpp

#include <iostream>
#include <string>

using namespace std;

string s = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";

int main() {
    int l = 1;    
    cout << " " << " ";
    for(auto& c : s) {
        cout << (char)(c + 32) << " ";
    }
    cout << endl;
    for(int i = 1; i < 27; i++,l++) {
        cout << i << " ";
        for(int j = l; j < 26; j++){
            cout << s[j] << " ";
        }
        for(int j = 0; j < l; j++){
            cout << s[j] << " ";
        }
        cout << endl;
    }
}   

运行截图:

任务6

实验任务7:

task7.cpp:

#include <cstdlib>
#include <iostream>
#include <string>

using namespace std;

int main() {
    int true_count = 0;
    for(int i = 0; i < 10; i++) {
        int op = rand() % 4;
        int l = 1,r = 2;
        int ans = 0; 
        srand(time(0));
        switch(op)  {
            case 0: {
                l = rand() % 10 + 1;
                r = rand() % 10 + 1;
                cout << l << " " << '+' << " " << r << " " << '=' << " ";
                cin >> ans;
                if(l + r == ans) true_count++;
                break;
            }
            case 1: {
                while(l < r) {
                    l = rand() % 10 + 1;
                    r = rand() % 10 + 1;
                }
                cout << l << " " << '-' << " " << r << " " << '=' << " ";
                cin >> ans;
                if(l - r == ans) true_count++;
                break;
            }
            case 2: {
                l = rand() % 10 + 1;
                r = rand() % 10 + 1;
                cout << l << " " << '*' << " " << r << " " << '=' << " ";
                cin >> ans;
                if(l * r == ans) true_count++;
                break;
            }
            case 3: {
                while(l % r != 0) {
                    l = rand() % 10 + 1;
                    r = rand() % 10 + 1;
                }
                cout << l << " " << '/' << " " << r << " " << '=' << " ";
                cin >> ans;
                if(l / r == ans) true_count++;
                break;
            }
        } 
    }
    cout << "正确率: " << true_count * 10 << ".00%" << endl;
}   

运行截图:

任务7

posted @ 2025-10-13 21:56  weiy404  阅读(6)  评论(0)    收藏  举报