摘要: <?php /* if($num%2 == 0){ echo "num是一个偶数"; } else{ echo"num是一个奇数"; } $grade = 81; if($grade > 80){ //满足条件$grade > 80 echo "该成绩的等级为优"; }elseif ($grade 阅读全文
posted @ 2020-10-20 09:21 _达不溜 阅读(136) 评论(0) 推荐(0)