摘要: 点击查看代码 #include <stdio.h> #define N 4 void test1() { int a[N] = {1, 9, 8, 4}; int i; printf("sizeof(a) = %d\n", sizeof(a)); for (i = 0; i < N; ++i) pr 阅读全文
posted @ 2024-05-19 17:07 雾矽 阅读(6) 评论(0) 推荐(0) 编辑