摘要:        
void Swap(int *i, int *j){ int temp = *i; *i = *j; *j = temp;}void MinHeapFixup(int a[], int i) { for (int j = (i - 1) / 2; (j >= 0 && i != 0)&& a[i] > a[j]; i = j, j = (i - 1) / 2) Swap(&a[i], &a[j]); }//在最小堆中加入新的数据nNum void MinHeapAddNumber(int a[], int n, int nNum) {    阅读全文
        
            posted @ 2012-10-09 17:51
Kalou
阅读(239)
评论(0)
推荐(0)
        
        
                    
                
浙公网安备 33010602011771号