摘要: int a=1,b=1; while(a++) { b = a*4-303; if(a*5==a+b+303&&b>0&&(a*5)%7==0&&b%((a*5)/7)==0)//&&b%7==0&&b>0) { printf("总数 = %d\n a = %d\n b = %d\n c = %d",a*5,... 阅读全文
posted @ 2016-12-03 19:14 疯陈演义 阅读(204) 评论(0) 推荐(0)