庚武讲堂

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突然发现某数据库的日志已经1.5G了，然而原来使用的截断日志的语句在2008中已经失效，在网上搜寻了一些方法，验证下面方法是有效的：首先检查目标数据库的恢复模式：SELECT NAME, recovery_model_desc FROM sys.databases如果是Full，则需要改为Simple:ALTER DATABASE Test SET Recovery simple然后收缩日志文件：DBCC SHRINKFILE (N'test_log' , 10)第一个参数是日志文件名，第二个参数是目标文件大小，以M为单位。第一个参数名可以用以下方法确定：USE DreamFr Read More

ini:[COMM] C0 = 0.1C1 = 0.25C2 = 0.35C3 = 0.45C4 = 0.55C5 = 0.56[POS_TAK]PT0 = 0.1PT1 = 1.1PT2 = 2.1PT3 = 3.1PT4 = 4.1PT5 = 5.1[BET_INFO]AMT = 100.23ODDS= 48.5 py:#!/usr/bin/env python#coding=gbkimport ConfigParserimport syscomm = [] #commissionpt = [] #position takingamt = 0.0 ... Read More

D:\oraclexe\app\oracle\product\10.2.0\server\NETWORK\ADMINtnsnames.oraXE = (DESCRIPTION = (ADDRESS = (PROTOCOL = TCP)(HOST = spark)(PORT = 1521)) (CONNECT_DATA = (SERVER = DEDICATED) (SERVICE_NAME = XE) ) )ORA254 =(DESCRIPTION = (ADDRESS_LIST = (ADDRESS = (PROTOCOL = TCP)(HOST... Read More

http://www.slyar.com/blog/win7-oracle-10g-error.html首先下对版本，Oracle 10g支持Win7版：http://download.oracle.com/otn/nt/oracle10g/10203/10203_vista_w2k8_x86_production_db.zip错误A：正在检查操作系统要求...要求的结果: 5.0,5.1,5.2,6.0 之一实际结果: 6.1检查完成。此次检查的总体结果为: 失败 <<<<问题: Oracle Database 11g 未在当前操作系统中经过认证。建议案: 确保在正确 Read More

conio.h不是C标准库中的头文件。conio是Console Input/Output（控制台输入输出）的简写，其中定义了通过控制台进行数据输入和数据输出的函数，主要是一些用户通过按键盘产生的对应操作，比如getch()函数等等。包含的函数： cgets(char *); cprintf(const char *, ...); cputs(const char *); cscanf(const char *, ...); inp(unsigned short); inpw(unsigned short); getch(void); getche(void); kbhit(... Read More

罗素－我为什么而活(中英文)What I have Lived For——Bertrand Russell Three passions,simple but overwhelmingly strong,have governed my life: the longing for love,the Read More

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http://madskristensen.net/post/A-NET-resource-editor-application-for-resx-files.aspxhttp://resourceeditor.codeplex.com/download: http://files.cnblogs.com/wucg/ResourceEditor.zip Read More

http://stackoverflow.com/questions/4591638/spring-net-ref-to-dictionary-item<object name="Paths" id="Paths" type="System.Collections.Generic.Dictionary&lt;string,string&gt;"> <constructor-arg> <dictionary key-type="string" value-type=&qu Read More