实验6 C语言结构体，枚举应用编程

task1

源代码

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 3

typedef struct student {
    int id;
    char name[20];
    char subject[20];
    double perf;
    double mid;
    double final;
    double total;
    char level[10];
}STU;

void input(STU[], int);
void output(STU[], int);
void calc(STU[], int);
int fail(STU[],STU[], int);
void sort(STU[], int);

int main() {
    STU st[N], fst[N];
    int k;

    printf("录入学生成绩信息:\n");
    input(st, N);

    printf("\n成绩处理...\n");
    calc(st, N);

    k = fail(st, fst, N);
    sort(st, N);
    printf("\n学生成绩排名情况；\n");
    output(st, N);

    printf("\n不及格学生信息；\n");
    output(fst, k);

    return 0;
}

void input(STU s[], int n) {
    int i;

    for (i = 0; i < n; i++)
        scanf("%d %s %s %lf %lf %lf", &s[i].id, s[i].name, s[i].subject, &s[i].perf, &s[i].mid, &s[i].final);
}

void output(STU s[], int n) {
    int i;

    printf("---------------\n");
    printf("学号  姓名  科目  平时  期中  期末  总评  等级\n");
    for (i = 0; i < n; i++)
        printf("%d %-6s %-4s %-4.0f %-4.0f %-4.0f %-4.1f %s\n", s[i].id, s[i].name, s[i].subject, s[i].perf, s[i].mid, s[i].final, s[i].total, s[i].level);

}

void calc(STU s[], int n) {
    int i;

    for (i = 0; i < n; i++) {
        s[i].total = s[i].perf * 0.2 + s[i].mid * 0.2 + s[i].final * 0.6;

        if (s[i].total >= 90)
            strcpy(s[i].level, "优");
        else if (s[i].total >= 80)
            strcpy(s[i].level, "良");
        else if (s[i].total >= 70)
            strcpy(s[i].level, "中");
        else if (s[i].total >= 60)
            strcpy(s[i].level, "及格");
        else
            strcpy(s[i].level, "不及格");
    }
}
int  fail(STU s[], STU t[], int n) {
    int i, cnt = 0;

    for (i = 0; i < n; i++)
        if (s[i].total < 60)
            t[cnt++] = s[i];

    return cnt;
}

void sort(STU s[], int n) {
    int i, j;
    STU t;

    for(i=0;i<n-1;i++)
        for(j=0;j<n-1-i;j++)
            if (s[j].total < s[j + 1].total) {
                t = s[j];
                s[j] = s[j + 1];
                s[j + 1] = t;
            }
}

 

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task2

源代码

#include<stdio.h>
#include<string.h>
#define N 10
#define M 80

typedef struct {
    char name[M];
    char author[M];
}book;

int main() {
    book x[N] = { {"《一九八四》", "乔治.奥威尔"},
{"《美丽新世界》", "赫胥黎"},
{"《昨日的世界》", "斯蒂芬.茨威格"},
{"《万历十五年》", "黄仁宇"},
{"《一只特立独行的猪》", "王小波"},
{"《百年孤独》", "马尔克斯"},
{"《查令十字街84号》", "海莲.汉芙"},
{"《只是孩子》", "帕蒂.史密斯"},
{"《刀锋》", "毛姆"},
{"《沉默的大多数》", "王小波"} };
    book* ptr;
    int i;
    char author[M];
    int found;

    printf("-----所有图书信息------\n");
    for (ptr = x; ptr < x + N; ++ptr)
        printf("%-30s%-30s\n", ptr->name, ptr->author);


    printf("\n--------按作者查询图书------\n");
    printf("输入作者名");
    gets(author);
        found = 0;
    for (ptr = x; ptr < x + N;++ptr)
        if (strcmp(ptr->author, author) == 0) {
            found = 1;
            printf("%-30s%-30\n", ptr->name, ptr - author);
        }

    if (!found)
        printf("暂未收录该作者书籍！\n");

    return 0;
}

 

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task3.1

源代码

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#define N 80

typedef struct FilmInfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo* next;
}Film;

void output(Film* head);
Film* insert(Film* head, int n);

int main() {
    int n; 
    Film* head; 

    head = NULL;
    printf("输入影片数目: ");
    scanf("%d", &n);

    head = insert(head, n);
    printf("\n所有影片信息如下: \n");
    output(head);
    return 0;
}

Film* insert(Film* head, int n) {
    int i;
    Film* p;

    for (i = 1; i <= n; ++i) {
        p = (Film*)malloc(sizeof(Film));
        printf("请输入第%d部影片信息: ", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);
    
        p->next = head;
        head = p; 
    }
    return head;
}

void output(Film* head) {
    Film* p;
    p = head;
    while (p != NULL) {
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year);
        p = p->next;
    }
}

 

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task3.2

源代码 

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#define N 80

typedef struct FilmInfo {
    char name[N];
    char director[N];
    char region[N];
    int year;
    struct FilmInfo* next;
}Film;

void output(Film* head);
Film* insert(Film* head, int n);

int main() {
    int n;
    Film* head;
    Film* p;

    p = (Film*)malloc(sizeof(Film));
    p->next = NULL;
    head = p;

    printf("输入影片数目：");
    scanf("%d", &n);

    head = insert(head, n);

    printf("\n所有影片信息:\n");
    output(head);

    return 0;
}
Film* insert(Film* head, int n) {
    int i;
    Film* p;

    for (i = 1; i <= n; ++i) {
        p = (Film*)malloc(sizeof(Film));
        printf("请输入第%d部影片信息", i);
        scanf("%s %s %s %d", p->name, p->director, p->region, &p->year);

        p->next = head->next;
        head->next = p;
    }
    return head;
}

void output(Film* head) {
    Film* p;

    p = head->next;
    while (p != NULL) {
        printf("%-20s %-20s %-20s %d\n", p->name, p->director, p->region, p->year);
        p = p->next;
    }
}

 

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task4

源代码

#include<stdio.h>
#define N 10

typedef struct {
    char isbn[20];
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
}Book;

void output(Book x[], int n);
void sort(Book x[], int n);
double sales_amount(Book x[], int n);

int main() {
    Book x[N] = { {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59} };

    printf("图书销量排名(按销售册数):\n");
    sort(x, N);
    output(x, N);

    printf("\n图书销售总额:%.2f\n",sales_amount(x,N));
    return 0;
}
void output(Book x[], int n) {
    printf("|ISBN号     |书名     |作者       |售价       |销售册数|\n");
    printf("|-----------|---------|-----------|-----------|--------|\n");
    for (int i = 0; i < n; i++) {
        printf("|%-19s|%-29s|%-19s|%-6.1f|%-8d|\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);

    }
}

void sort(Book x[], int n) {
    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - 1 - i; j++) {
            if (x[j].sales_count < x[j + 1].sales_count) {
                Book temp = x[j];
                x[j] = x[j + 1];
                x[j + 1] = temp;
            }
        }
    }
}

double sales_amount(Book x[], int n) {
    double total = 0.0;
    for (int i = 0; i < n; i++) {
        total += x[i].sales_price * x[i].sales_count;
    }
    return total;
}

 

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task5

源代码

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
typedef struct {
    int year;
    int month;
    int day;
}Date;

void input(Date* pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);

void test1() {
    Date d;
    int i;

    printf("输入日期：(以形如2025-06-01这样的形式输入)\n");
    for (i = 0; i < 3; ++i) {
        input(&d);
        printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
    }
}

void test2() {
    Date Alice_birth, Bob_birth;
    int i;
    int ans;

    printf("输入Alice和Bob出生日期：（以形如2025-06-01这样的形式输入）\n");
    for (i = 0; i < 3; ++i) {
        input(&Alice_birth);
        input(&Bob_birth);
        ans = compare_dates(Alice_birth, Bob_birth);

        if (ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if (ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
    }
}
int main() {
    printf("测试1；输入日期，打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2：两个人年龄大小关系\n");
    test2();
}
void input(Date* pd) {
    scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
}
int day_of_year(Date d) {
    int days = d.day;
    int month_days[] = { 31,28,31,30,31,30,31,31,30,31,30,31 };

    if ((d.year % 4 == 0 && d.year % 100 != 0) || d.year % 400 == 0) {
        month_days[1] = 29;
    }
    for (int i = 0; i < d.month - 1; i++) {
        days += month_days[i];
    }
    return days;
}

int compare_dates(Date d1, Date d2) {
    if (d1.year < d2.year)return -1;
    if (d1.year > d2.year)return 1;

    if (d1.month < d2.month)return -1;
    if (d1.month > d2.month)return 1;

    if (d1.day< d2.day)return -1;
    if (d1.day > d2.day)return 1;

    return 0;
}

 

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task6

源代码

#include<stdio.h>
#include<string.h>

enum role{admin,student,teacher};

typedef struct {
    char username[20];
    char password[20];
    enum role type;
}Account;

void output(Account x[], int n);

int main() {
    Account x[] = { {"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student} };
    int n;
    n = sizeof(x) / sizeof(Account);
    output(x, n);

    return 0;
}
void output(Account x[], int n) {
    for (int i = 0; i < n; i++) {
        int len = strlen(x[i].password);
        char stars[20];
        for (int j = 0; j < len; j++) {
            stars[j] = '*';
        }
        stars[len] = '\0';

        const char *role=0;
        switch (x[i].type) {
        case admin:role = "admin"; break;
        case student:role = "student"; break;
        case teacher:role = "teacher"; break;
        defaut:role = "unknown"; break;
        }
        printf("%-10s%-12s%s\n", x[i].username, stars, role);
    }
}

 

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task7

源代码

#define _CRT_SECURE_NO_WARNINGS

#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];     
    char phone[12];    
    int  vip;           
} Contact;



void set_vip_contact(Contact x[], int n, char name[]);  
void output(Contact x[], int n);    
void display(Contact x[], int n);  


#define N 10
int main() {
    Contact list[N] = { {"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0} };
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n");
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);

    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for (i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}
void set_vip_contact(Contact x[], int n, char name[]) {
    for (int i = 0; i < n; i++) {
        if (strcmp(x[i].name,name) == 0) {
            x[i].vip = 1;
            break;
        }
    }
}
void display(Contact x[], int n) {
    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - i - 1; j++) {
            if (x[j].vip == x[j + 1].vip) {
                if (strcmp(x[j].name, x[j + 1].name) > 0) {
                    Contact temp = x[j];
                    x[j] = x[j + 1];
                    x[j + 1] = temp;
                }
            }
            else if (x[j].vip < x[j + 1].vip) {
                Contact temp = x[j];
                x[j] = x[j + 1];
                x[j + 1] = temp;
            
            }
        }
    }
    for (int i = 0; i < n; i++) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip) {
            printf("%5s", "*");
        }
        printf("\n");
    }
}
void output(Contact x[], int n) {
    for (int i = 0; i < n; i++) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip) {
            printf("%5s", "*");
        }
        printf("\n");
    }
}

 

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