实验4C语言数组应用编程

task1

源代码

#include<stdio.h>
#define N 4
#define M 2

void test1() {
    int x[N] = { 1,9,8,4 };
    int i;

    printf("sizeof(x)=%d\n", sizeof(x));
    for (i = 0; i < N; ++i)
        printf("%p:%d\n", &x[i], x[i]);
    printf("x=%p\n", x);
}
void test2() {
    int x[M][N] = { {1,9,8,4},{2,0,4,9} };
    int i, j;

    printf("sizeof(x)=%d\n", sizeof(x));

    for (i = 0; i < M; ++i)
        for (j = 0; j < N; ++j)
            printf("%p:%d\n", &x[i][j], x[i][j]);
    printf("\n");
    printf("x=%p\n", x);
    printf("x[0]=%p\n", x[0]);
    printf("x[1]=%p\n", x[1]);
    printf("\n");
}
int main() {
    printf("测试1:int型一维数组\n");
    test1();

    printf("\n测试2：int型二维数组\n");
    test2();

    return 0;
}

 

问题1：是连续存放的，数组名x和&x[0]对应的值一样

问题2：是按行连续存放的，其值在字面上一样，相差16

task2

源代码

#define N 100

void input(int x[], int n);
double compute(int x[], int n);

int main() {
    int x[N];
    int n, i;
    double ans;

    while (printf("Enter n:"), scanf_s("%d", &n) != EOF) {
        input(x, n);
        ans = compute(x, n);
        printf("ans=%.2f\n\n", ans);
    }
    return 0;
}
void input(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        scanf_s("%d", &x[i]);
}
double compute(int x[], int n) {
    int i, high, low;
    double ans;

    high = low = x[0];
    ans = 0;

    for(i=0;i<n;++i){
    ans += x[i];

    if (x[i] > high)
        high = x[i];
    else if (x[i] < low)
        low = x[i];
}

ans = (ans - high - low) / (n - 2);

return ans;
}

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问题：input函数的功能是输入数组所含数据的个数和数据，compute函数的功能是计算数组中除去最大值和最小值后数据的平均值

task3

源代码

#include<stdio.h>
#define N 100

void output(int x[][N], int n);
void init(int x[][N], int n, int value);

int main() {
    int x[N][N];
    int n, value;

    while (printf("Enter n and value:"), scanf_s("%d %d", &n, &value) != EOF) {
        init(x, n, value);
        output(x, n);
        printf("\n");
    }

    return 0;
}

void output(int x[][N], int n) {
     int i, j;

    for (i = 0; i < n; ++i) {
        for (j = 0; j < n; ++j)
            printf("%d", x[i][j]);
        printf("\n");
    }
}

void init(int x[][N], int n, int value) {
    int i,j;
        
    for (i = 0; i < n; ++i)
        for (j = 0; j < n; ++j)
            x[i][j] = value;
}

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问题1：第二维的大小不能省略

问题2：output函数功能是按行和列格式速出一个n*n的二维数组，init函数功能是初始化一个n*n的二维数组

 

task4

源代码

#include<stdio.h>
#define N 100

void input(int x[], int n);
double median(int x[], int n);

int main() {
    int x[N];
    int n;
    double ans;

    while (printf("Enter n:"), scanf_s("%d", &n) != EOF) {
        input(x, n);
        ans = median(x, n);
        printf("ans=%.1f\n\n", ans);
    }
    return 0;
}
void input(int x[], int n) {
    printf("Enter %d numbers:", n);
    for (int i = 0; i < n; ++i) {
        scanf_s("%d", &x[i]);
    }
}

double median(int x[], int n) {

    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - i - 1; j++) {
            if (x[j] > x[j + 1]) {
                int temp = x[j];
                x[j] = x[j + 1];
                x[j + 1] = temp;
            }
        }
    }
    if (n % 2 == 1) {
        return x[n / 2];
    }
    else {
        return(x[n / 2 - 1] + x[n / 2] )/ 2.0;
    }
}

 

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task5

源代码

#include<stdio.h>
#define N 100

void input(int x[][N], int n);
void output(int x[][N], int n);
void rotate_to_right(int x[][N], int n);

int main() {
    int x[N][N];
    int n;

    printf("Enter n:");
    scanf_s("%d", &n);
    input(x, n);

    printf("原始矩阵:\n");
    output(x, n);

    rotate_to_right(x, n);

    printf("变换后的矩阵:\n");
    output(x, n);

    return 0;
}

void input(int x[][N], int n) {
    int i, j;

    for (i = 0; i < n; ++i) {
        for (j = 0; j < n; ++j)
            scanf_s("%d", &x[i][j]);
    }
}
void output(int x[][N], int n) {
    int i, j;
    for (i = 0; i < n; ++i) {
        for (j = 0; j < n; ++j)
            printf("%d", x[i][j]);
        printf("\n");
    }
}

void rotate_to_right(int x[][N], int n) {
    int temp[N];
    int i, j;

    for (i = 0; i < n; ++i) {
        temp[i] = x[i][n - 1];
    }

    for (j = n - 1; j > 0; --j) {
        for (i = 0; i < n; ++i) {
            x[i][j] = x[i][j - 1];
        }
    }
    for (i = 0; i < n; ++i) {
        x[i][0] = temp[i];
    }
}

 

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task6

源代码

#include<stdio.h>
#define N 100

void dec_to_n(int x, int n);

int main() {
    int x;

    while (printf("输入十进制整数："), scanf_s("%d", &x) != EOF) {
        dec_to_n(x, 2);
        dec_to_n(x, 8);
        dec_to_n(x, 16);

        printf("\n");
    }

    return 0;
}

void dec_to_n(int x, int n) {
    char digits[N];
    int i = 0;
    int remainder;
    int original_x = x;

    if (x == 0) {
        printf("0\n");
        return;
    }
    if (x < 0) {
        x = -x;
    }
    while (x > 0) {
        remainder = x % n;
        if (remainder < 10) {
            digits[i] = remainder + '0';
        }
        else {
            digits[i] = remainder - 10 + 'A';
        }
        x = x / n;
        i++;
    }
    if (original_x < 0) {
        printf("-");
    }

    for (int j = i - 1; j >= 0; j--) {
        printf("%c", digits[j]);
    }
    printf("\n");
}

 

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 task7

源代码

#include<stdio.h>

int main() {
    for (int num = 1; num < 100000; num++) {
        int square = num * num;
        int cube = num * num * num;
         long  combined = 0;
        int temp = square;
        while (temp > 0) {
            combined = combined * 10 + temp % 10;
            temp /= 10;
        }
        temp = cube;
        while (temp > 0) {
            combined = combined * 10 + temp % 10;
            temp /= 10;
        }
        int digits[10] = { 0 };
        int valid = 1;
      long check = combined;

        while (check > 0) {
            int digit = check % 10;
            digits[digit]++;
            if (digits[digit] > 1) {
                valid = 0;
                break;
            }
            check /= 10;
        }
        if (valid) {
            for (int i = 0; i < 10; i++) {
                if (digits[i] != 1) {
                    valid = 0;
                    break;
                }
            }
        }
        if (valid) {
            printf("找到符合条件的数字:%d\n", num);
            printf("平方:%d,立方:%d\n", square, cube);
            return 0;
        }
    }
    printf("没有找到。\n");
    return 0;

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